GCSE (9–1) Mathematics J560/06: Paper 6 (Higher tier) General Certificate of Secondary Education Mark Scheme for November 2020

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GCSE (9–1) Mathematics J560/06: Paper 6 (Higher tier) General Certificate of Secondary Education Mark Scheme for November 2020 Oxford Cambridge and RSA Examinations H GCSE (9–1) Mathemat... ics J560/06: Paper 6 (Higher tier) General Certificate of Secondary Education Mark Scheme for November 2020Oxford Cambridge and RSA Examinations OCR (Oxford Cambridge and RSA) is a leading UK awarding body, providing a wide range of qualifications to meet the needs of candidates of all ages and abilities. OCR qualifications include AS/A Levels, Diplomas, GCSEs, Cambridge Nationals, Cambridge Technicals, Functional Skills, Key Skills, Entry Level qualifications, NVQs and vocational qualifications in areas such as IT, business, languages, teaching/training, administration and secretarial skills. It is also responsible for developing new specifications to meet national requirements and the needs of students and teachers. OCR is a not-for-profit organisation; any surplus made is invested back into the establishment to help towards the development of qualifications and support, which keep pace with the changing needs of today’s society. This mark scheme is published as an aid to teachers and students, to indicate the requirements of the examination. It shows the basis on which marks were awarded by examiners. It does not indicate the details of the discussions which took place at an examiners’ meeting before marking commenced. All examiners are instructed that alternative correct answers and unexpected approaches in candidates’ scripts must be given marks that fairly reflect the relevant knowledge and skills demonstrated. Mark schemes should be read in conjunction with the published question papers and the report on the examination. © OCR 2020J560/06 Mark Scheme November 2020 2 1. Annotations available in RM Assessor. These must be used whenever appropriate during your marking. Annotation Meaning Correct Incorrect Benefit of doubt Follow through Ignore subsequent working (after correct answer obtained), provided method has been completed Method mark awarded 0 Method mark awarded 1 Method mark awarded 2 Accuracy mark awarded 1 Independent mark awarded 1 Independent mark awarded 2 Misread Special case Omission sign Blank page Seen For a response awarded zero (or full) marks a single appropriate annotation (cross, tick, M0 or ^) is sufficient, but not required.J560/06 Mark Scheme November 2020 3 For responses that are not awarded either 0 or full marks, you must make it clear how you have arrived at the mark you have awarded and all responses must have enough annotation for a reviewer to decide if the mark awarded is correct without having to mark it independently. It is vital that you annotate standardisation scripts fully to show how the marks have been awarded. Subject-Specific Marking Instructions 2. M marks are for using a correct method and are not lost for purely numerical errors. A marks are for an accurate answer and depend on preceding M (method) marks. Therefore M0 A1 cannot be awarded. B marks are independent of M (method) marks and are for a correct final answer, a partially correct answer, or a correct intermediate stage. SC marks are for special cases that are worthy of some credit. 3. The following abbreviations are commonly found in GCSE Mathematics mark schemes. - figs 237, for example, means any answer with only these digits. You should ignore leading or trailing zeros and any decimal point e.g. 237000, 2.37, 2.370, 0.00237 would be acceptable but 23070 or 2374 would not. - isw means ignore subsequent working after correct answer obtained and applies as a default. - nfww means not from wrong working. - oe means or equivalent. - rot means rounded or truncated. - soi means seen or implied. - dep means that the marks are dependent on the marks indicated. You must check that the candidate has met all the criteria specified for the mark to be awarded. - with correct working means that full marks must not be awarded without some working. The required minimum amount of working will be defined in the guidance column and SC marks given for unsupported answers. 4. Anything in the mark scheme which is in square brackets […] is not required for the mark to be earned, but if present it must be correct. 5. Unless the command word requires that working is shown and the working required is stated in the mark scheme, then if the correct answer is clearly given and is not from wrong working full marks should be awarded. Do not award the marks if the answer was obtained from an incorrect method, i.e. incorrect working is seen and the correct answer clearly follows from it. 6. Where follow through (FT) is indicated in the mark scheme, marks can be awarded where the candidate’s work follows correctly from a previous answer whether or not it was correct. For questions with FT available you must ensure that you refer back to the relevant previous answer. You may find it easier to mark these questions candidate by candidate rather than question by question.J560/06 Mark Scheme November 2020 4 Figures or expressions that are being followed through are sometimes encompassed by single quotation marks after the word their for clarity, e.g. FT 180 × (their ‘37’ + 16), or FT 300 – √(their ‘52 + 72’). Answers to part questions which are being followed through are indicated by e.g. FT 3 × their (a). 7. In questions with no final answer line, make no deductions for wrong work after an acceptable answer (i.e. isw) unless the mark scheme says otherwise, indicated by the instruction ‘mark final answer’. 8. In questions with a final answer line and incorrect answer given: (i) If the correct answer is seen in the body of working and the answer given on the answer line is a clear transcription error allow full marks unless the mark scheme says ‘mark final answer’. Place the annotation  next to the correct answer. (ii) If the correct answer is seen in the body of working but the answer line is blank, allow full marks. Place the annotation  next to the correct answer. (iii) If the correct answer is seen in the body of working but a completely different answer is seen on the answer line, then accuracy marks for the answer are lost. Method marks could still be awarded if there is no other method leading to the incorrect answer. Use the M0, M1, M2 annotations as appropriate and place the annotation  next to the wrong answer. 9. In questions with a final answer line: (i) If one answer is provided on the answer line, mark the method that leads to that answer. A correct step, value or statement that is not part of the method that leads to the given answer should be awarded M0 and/or B0. (ii) If more than one answer is provided on the answer line and there is a single method provided, award method marks only. (iii) If more than one answer is provided on the answer line and there is more than one method provided, award marks for the poorer response unless the candidate has clearly indicated which method is to be marked. 10. In questions with no final answer line: (i) If a single response is provided, mark as usual. (ii) If more than one response is provided, award marks for the poorer response unless the candidate has clearly indicated which response is to be marked.J560/06 Mark Scheme November 2020 5 11. When the data of a question is consistently misread in such a way as not to alter the nature or difficulty of the question, please follow the candidate’s work and allow follow through for A and B marks. Deduct 1 mark from any A or B marks earned and record this by using the MR annotation. M marks are not deducted for misreads. If a candidate corrects the misread in a later part, do not continue to follow through, but award A and B marks for the correct answer only. 12. Unless the question asks for an answer to a specific degree of accuracy, always mark at the greatest number of significant figures even if this is rounded or truncated on the answer line. For example, an answer in the mark scheme is 15.75, which is seen in the working. The candidate then rounds or truncates this to 15.8, 15 or 16 on the answer line. Allow full marks for the 15.75. 13. Ranges of answers given in the mark scheme are always inclusive. 14. For methods not provided for in the mark scheme give as far as possible equivalent marks for equivalent work. If in doubt, consult your Team Leader. 15. If in any case the mark scheme operates with considerable unfairness consult your Team Leader.J560/06 Mark Scheme November 2020 6 Question Answer Marks Part marks and guidance 1 (a) Points plotted at (210, 130) and (100, 80) 2 B1 for 100 soi or for one point plotted correctly Half square tolerance May be implied by point plotted at duration 100 (b) Point at (220, 64) circled 1 (c) (i) Ruled line of best fit drawn 1 Use overlay anchored on top right point Line must reach to edges of overlay (ii) Their line used to give duration for £90 ± 5 minutes 1 FT Strict FT from their intended straight line of best fit NB read (n, 90) not (90, n) (d) [7 hours is] is beyond the given data oe 1 Accept eg the trend may not continueJ560/06 Mark Scheme November 2020 7 Question Answer Marks Part marks and guidance 2 x < 5 AND 4 B2 for x < 5 or M1 for 3x < 19 – 4 or better AND B2FT for x < 5, or their inequality, correctly shown or B1FT for x < 5, or their inequality, shown with a hollow circle and wrong arrow or filled circle and correct arrow Solution to inequality: Allow M1 for this expression with other inequality symbols or equals sign or [x =] 5 as solution (can be implied by mark/circle on the diagram) or trials leading to selection of 5 or final correct trial using 5 Displaying the solution: Display must show an inequality that fits on the number line for FT Mark to candidate’s advantage either x < 5 or their inequality Accept an arrow of any length or a line reaching 1 If no solution to inequality seen: Hollow circle at 5 arrow to left M1B2 Filled circle at 5 arrow to left M1B1 Hollow circle at 5 arrow to right M1B1 Filled circle at 5 arrow to right M1B0 Mark at 5 no line or arrow M1B0 Circle and/or arrow at other than 5 M0B0J560/06 Mark Scheme November 2020 8 Question Answer Marks Part marks and guidance 3 (a) 55.5[0] to 57.[0] nfww 3 M1 for 1 kwH costs £0.125 oe soi M1 for their 0.125 × 450 or cost × 450 �ℎ��� equivalent electricity use OR M1 for finding costs of electricity that sum to 450 kwH M1 for addition of these costs eg 225 kwH costs £28.125 ± £0.5[0] 200 kwH costs £25 ± £0.5[0] 150 kwH costs £18.75 ± £0.5[0] 100 kwH costs £12.5 ± £0.5[0] 50 kwH costs £6.25 ± £0.5[0] eg 25 × 450 200 eg award M2 for 4 × (£12.5 ± £0.5[0]) + (£6.25 ± £0.5[0]) For the first M1 mark, costs must be from graph within ±½ small square ie ±£0.5[0]J560/06 Mark Scheme November 2020 9 Question Answer Marks Part marks and guidance (b) Method 1: By performing a calculation for A and comparing with B: 12.5 or 0.125 or “cost ÷ usage” using a reading from the graph or their (a) ÷ 450 14.3 or 0.143 stated or comparison against it clearly implied in a statement “B” with 12.5 and 14.3 or “B” with 0.125 and 0.143 or “B” with 12.5 or 0.125 and a comparison against 14.3 or 0.143 clearly implied 1 1dep 1 Method 2: By performing a calculation for B and comparing with A: 14.3 × their chosen usage soi or [0].143 × their chosen usage soi May be implied by line on graph Cost in p or £ from graph for their chosen usage stated “B” with both costs correct and in same units Mark method not accuracy for first two marks e.g. 6.75 ÷ 50 = 0.135 but not 0.135 with no working Dep on first mark scored. Costs for A and B may be in different units. e.g. 1kwH costs 12.5p which is less than Company B’s charge No follow through e.g. B because 1kwH costs 12.5p which is less than Company B’s charge 4 (a) e.g. ��04.5××400 200�3 = √163 = 64 3 B2 for 4, 400, 0.5 and 200 or B1 for at least two of 4, 400, 0.5 and 200 For full marks, at least one of these intermediate steps leading to 64 must be seen √163 or 43 or √4096J560/06 Mark Scheme November 2020 10 Question Answer Marks Part marks and guidance (b) 38.7 to 38.9 4 B2 for 46.1 to 46.11 or 17.89 to 17.9 or B1 for 12.8 to 12.9 or 3.57 to 3.6[0] or 2125 to 2126 and M1 for (64 – their 46.1 to 46.11) ÷ their 46.1 to 46.11 [× 100] oe Accept 39 with correct working 5 (a) 30 final answer 2 B1 for 150 or 30 seen or M1 for 360 ÷ 12 oe e.g. 180 10 180 12 × − (b) 150 or FT(180 – (a)) 1 Only allow FT if 0 < their (a) < 180J560/06 Mark Scheme November 2020 11 Question Answer Marks Part marks and guidance 6 385 with correct working 6 M2 for [mass of one panel =] 2.4 × 1.2 × 0.018 × 750 or 240 × 120 × 1.8 × 0.750 or M1 for figs 24 × figs 12 × figs 18 × figs 750 or 2.4 × 1.2 × 0.018 or 240 × 120 × 1.8 AND B1 for 15000 [kg] or 15000000g seen or their mass correctly converted to tonnes M1 for ���� 15 �ℎ��� ���� A1 for 385.[…] to 387 If 0 or B1 scored, instead award SC2 for answer 385 with no working or insufficient working If 0 scored SC1 for answer 385.[…] to 387 with no working “Correct working” requires evidence of at least M2 AND B1 i.e. correct and consistent units used soi by 38.8 to 38.9 [kg] soi by 38800 to 38900 [g] soi by 0.0518 to 0.0519 [m3] soi by 51800 to 51900 [cm3] Assume their mass unit from M2, but do not assume from M1 only Accept any figure but not 2.4, 1.2, 1.8 and 750 for their mass For M1 accept one or more trial(s) of their mass × an integer in attempt to = their figs 15J560/06 Mark Scheme November 2020 12 Question Answer Marks Part marks and guidance 7 (a) �−42� 2 B1 for 1 component correct If 0 scored, then SC1 for �−24� or 4 2       − or (4, -2) Penalise first appearance of vinculum or poor form in vector but condone second use (b) �19 4� oe 2 B1 seen for 1 component correct or �4 9�J560/06 Mark Scheme November 2020 13 Question Answer Marks Part marks and guidance 8 31 nfww 4 M2 for 20 : 10 or 20 30 and 21 : 9 or 21 30 and SC1 for final answer 30 dep on M2 OR M1 for at least one other fraction equivalent to 2 3 seen, or one other fraction equivalent to 7 10 seen Alternative method using algebra M1 for �−1 �−1 = 2 3 oe or � �−1 = 7 10 oe M1 for 3(r – 1) = 2(t – 1) and 10r = 7(t – 1) or better M1 for elimination or substitution of r If 0 scored SC1 for answer 30 with no working Notes on alternative method Where number of red = r. Does not need to be defined. Accept any other letter. Implies first M1 mark A correct equation in b may imply first M1M1 marksJ560/06 Mark Scheme November 2020 14 Question Answer Marks Part marks and guidance 9 z = 1.2x or z = 6� 5 4 B3 for a correct equation involving just x and z but not in required form OR B1 for y = 6x oe B1 for y = 5z oe M1 for a correct equation involving just x and z using their two equations OR B1 for y = 60 when z = 12 B1 for x : [y :] z is 10 : [60 :]12 M1 for a correct equation involving just x and z using their triple ratio or their two ratios with a common y value If 0 scored SC1 for y = kx and k = 6 found oe or for y = kz and k = 5 found oe Condone ∝ for = in B1 marks and SC1 but not at B3 or full marks e.g. 5z = 6x, or x = 5� 6 Their two equations of the form y = ax oe and y = bz oe Allow B2 for other triple ratios of the form 5k : 30k : 6k or two correct ratios with a common y valueJ560/06 Mark Scheme November 2020 15 Question Answer Marks Part marks and guidance 10 22 3 M2 for 1.403 ÷ 1.15 oe soi by 1.22 or B1 for 1.15 soi Alternative method : If starting from (1 + k/100) × 1.15 = 1.403 M2 for reaching 1.15k/100 = 0.253 or B1 for the 1.15 Condone answer 22% 11 (a) (i) 7 4 M2 for 3x + 15 = 2(x + 11) oe or M1 for 3x + 15 or 2(x + 11) oe M1 for a productive step towards solving their linear equation Alternative method by trials: M2 for at least two complete trials using the same inputs for both functions or M1 for one complete trial using the same input for both functions A1 for at least one correct evaluation for A and one for B Starting equation must have x on both sides e.g. from 3x + 15 = 2(x + 11): M1 for 2x + 22 or x + 15 = 22 or 3x = 2x + 7 or 1.5x + 7.5 = x + 11 e.g. from 3x + 15 = 2x + 11: M1 for x + 15 = 11 or 3x = 2x – 4J560/06 Mark Scheme November 2020 16 Question Answer Marks Part marks and guidance (ii) Because 3x + 15 and 2(x + 11) are not equivalent oe OR 3x + 15 = 2(x + 11) only has one solution oe 1 If not using the words ‘not equivalent’, must clearly imply that the two expressions will not be equal for all values of x The mark is unlikely to be awarded unless algebra is used (b) p = 5, q = 3 3 B1 for p = 5 or q = 3 M1 for q(x + p) oe or [3x + 15 =] 3(x + p) or [3x + 15 =] q(x + 5) If no working SC1 for p = 3 and q = 5 as answers May be seen with a particular value of x, eg. q(2 + p) 12 4 28 oe or 0.1428 to 0.143 3 M1 for 4 correct combinations soi by highlighting in list or table or by unsimplified numerator 4 M1 for 4 × 7 soi by complete list or table or by 28 Alternative method M2 for �1 4 × 1 7� + �1 4 × 2 7� + �1 4 × 1 7� oe or M1 for 1 4 × 1 7 or 1 4 × 2 7 oe seen Economics Engineering Geography German Geography Graphics Media MusicJ560/06 Mark Scheme November 2020 17 13 50 4 B1 for 2.5 oe soi M2 for 8 × (5 ÷ 2)2 oe or M1 for (5 ÷ 2)2 soi by 6.25 oe Alternative method: B1 for [AB : AC =] 2 : 5 oe soi M2 for (8 ÷ 22) × 52 oe or M1 for [area ratio] 22 : 52 oe soi Alternative method: B1 for 2.5 oe soi M1 for numerical � × ℎ 2 = 8 where b × h = 16 M1 for 2.5 �ℎ��� � × 2.5 �ℎ��� ℎ 2 If evidence of using 2 : 3 seen: B0 for [AB : AC =] 2 : 3 or 1.5 oe soi M2 for (8 ÷ 22) × 32 oe or M1 for [area ratio] 22 : 32 or 1.52 oe soi If no working: SC1 for final answer 18 Final answer 20 implies B1 (from use of linear scale factor) 6.25 scores B1M1 22 : 52 scores May be seen in stagesJ560/06 Mark Scheme November 2020 18 Question Answer Marks Part marks and guidance 14 2.99 [cm] with correct working 5 M3 for 5 3 ��3 + ��3 = 225 soi by 8 3 ��3 = 225 A1 for 3�675 8� or 3√26.8 to 3√26.9 or M2 for 1 3 ��2 × 5� + ��2 × � oe soi by 8 3 ��3 or M1 for 1 3 ��2 × 5� oe or ��2 × � oe If 0 or M1 scored, instead award SC2 for answer 2.99 or greater rot accuracy of 2.9947090608… with no working or insufficient working If 0 scored SC1 for 3�675 8� or 3√26.8 to 3√26.9 with no working “Correct working” requires evidence of at least M2 Accept 2.99 or greater rot accuracy of 2.9947090608 with correct working Accept 3[.0] as final answer only after M3A1 Trials: Full marks for trials leading to an answer 2.99 or greater rot accuracy of 2.9947090608… Trials leading to any other final answer, including 3[.0], only score the M marks if seenJ560/06 Mark Scheme November 2020 19 Question Answer Marks Part marks and guidance 15 9 16 or [0].5625 oe 4 B1 for 0.75 oe seen M2 for 0.25 × 0.3 + their 0.75 × 0.65 or M1 for 0.25 × 0.3 soi by 0.075 or 3 40 oe or for their 0.75 × 0.65 soi by 0.4875 or 39 80 oe Accept [0].56 or [0].563 as final answer for full marks if B1M2 earned Award B and M marks for equivalent working with a base value e.g. 100 buses 16 (a) [angle in a] semi-circle oe 1 Accept other reasoning if fully justified (b) 13.5 to 13.6 4 B1 for angle BAC = 58˚ or angle ABC = 32˚ M2 for 16sin(their 58) or 16cos(their 32) or M1 for sin(�ℎ��� 58) = �� �ℎ��� 16 or cos(�ℎ��� 32) = �� �ℎ��� 16 or better If 0 or B1 scored then instead award SC2 for 6.7 to 6.8 as final answer Grads or rads: If 0, 1 or 2 scored then instead award SC3 for 15.8[8…] to 15.9 or 12.6[4…] as final answer or If 0 scored award SC1 for 7.9[4…] or 6.3[2…] May be seen on diagram or implied by use of sin58 or cos32 Only award M marks if their angle and trig ratio are consistent ie do not accept 16sin32 unless angle BAC previously seen as 32.J560/06 Mark Scheme November 2020 20 Question Answer Marks Part marks and guidance 17 (a) 75 1 (b) 3 [×]�√5��−1 oe 3 M2 for expression of correct form with two correct elements or M1 for expression of correct form with one correct element eg 3 [×]�√5�� eg 5 [×]�√5�� 18 412 990 = 206 495 with correct working or 41.2 99 = 206 495 with correct working 3 M2 for 1000x [–] 10x = 416.16[1...] [–] 4.16[1...] leading to 990x = 412 or for 100x [–] x = 41.616[1…] [–] 0. 416[1...] leading to 99x = 41.2 or M1 for 10x = 4.16[1…] or 100x = 41.616[1…] or 1000x = 416.16[1…] seen “Correct working” requires M2 Subtractions can be implied 19 (a) [x =] -3, 1.5 2 B1 for 1 correct (b) (i) [a =] 2 [b =] -5 2 B1 for each or for 2x – 5 seenJ560/06 Mark Scheme November 2020 21 Question Answer Marks Part marks and guidance (ii) y = 2x – 5 or FT y = their ax + their b ruled on grid 1.1 to 1.3 and -1.8 to -1.6 M2 A1 M2 and M1 apply to y = 2x – 5 or FT y = their ax + their b M1 for ‘correct’ y-intercept or for ‘correct’ gradient or for freehand or broken ‘correct’ line or for at least 3 ‘correct’ plots and no ‘incorrect’ plots For M2 line must cross curve For M2 and M1, accuracy 1 small square at y-intercept (extended if necessary provided it fits on the grid) and gradient ±1 small square vertically for a run of 1 unit horizontally Do not FT if a = 0 or b = 0 Only award if M2 scored 20 -9 4 M2 for �2� +7 11� or M1 for � 7 � or �2� + 11� or �24�� M1 for (their 2k + 11) = – (their 7) their 7 must follow from their working for M2 and must not be -1J560/06 Mark Scheme November 2020 22 Question Answer Marks Part marks and guidance 21 2 1 2 x x − + as final answer 6 M1 for x² – 4 = (x + 2)(x – 2) soi in the denominator AND M3 for all 3 fractions combined with quadratic common denominator and expanded numerator or M2 for correct products on numerator of at least 2 equivalent fractions that are consistent with their common denominators or M1 for correct product on numerator of 1 fraction that is consistent with an attempted common denominator AND M1dep for (2�−1)(�−2) (�+2)(�−2) or (2�−1)(�−2) �2−4 (dep on previous M3 earned) e.g. 6� (�+2)(�−2) seen, or a common denominator of (x + 2)(x – 2) later expanded to x² – 4 e.g. �2−2�+�2+�+2�+2−6� (�+2)(�−2) soi by 2�2−5�+2 (�+2)(�−2) e.g. �(�−2) (�+2)(�−2) oe and ( (�+1 �+2)( )(�+2 �−2) ) oe e.g. �(�−2) (�+2)(�−2) oe Factorises numerator of combined fraction Can earn up to M1 + M2 + M0 for common denominator used that is not in its lowest terms. eg. M0 + M2 for �(�−2)��2−4� (�+2)(�−2)(�2−4) and (�+1)(�+2)��2−4� (�+2)(�−2)(�2−4) eg. M1 + M1 for �(�−2)(�+2)(�−2) (�+2)(�−2)(�+2)(�−2)J560/06 Mark Scheme November 2020 23 Q1(d) Response Mark No because it does not have a record for 7 hours This scores 0 as there is no record for e.g. 80 min. Must imply “beyond” 0 7 hours isn't on the scale. No. Implies a bigger diagram would be OK 0 No Because 420 minutes is too long to fit on the graph Implies it would be OK with a bigger graph 0 No It only shows 2h 50 minutes Suggests 7 hours is a missing value 0 No It would go up to 4200. No implies scale not long enough 0 No Highest duration is 250 mins which isn't 7 hours. 420 mins is 7 hours. No. Implies a bigger diagram would be OK 0 No His records only go up to 4hours 10minutes. No. This is about the scale. However, if they had said 4 hours, then they would have been talking about the data 0 No It does not show this information. 7x60 = 420mins. Graph only goes up to 250mins. No scale again 0 No His record doesn't show any 7 hour flights. No. Implies it is a missing value 0 No It would not fit on the graph. No. Implies it is a missing value 0 No Duration only goes to 250 mins. No. Implies it is a missing value 0 No Graph does not go beyond 250 minutes. 60x7 = 420mins. No. Implies it is a missing value 0 No Duration does not go up to 7 hours. No. Implies a bigger diagram would be OK 0 No Extrapolation Not explained 0 No. Should not extrapolate beyond 250 minutes/the graph Graph not big enough 0 No. Extrapolating too far meaning his estimate would be inaccurate Not quite sufficiently clear. What is “too far” and is it from 240 or 250? 0 No. The data only shows a maximum of a 250 minute flight so this would be unreliable Contradiction. 240 rather than 250 would have been acceptable. 0 No There are only less amount of flights on the diagram. Yes. This implies “beyond the data” 1 No because the duration only goes up to 240 minutes Scores the mark for implying beyond the data 1 No because it does not have records that go as far as 7 hours. This is OK as it implies “beyond” 1 No. Should not extrapolate beyond 240 minutes/the data Beyond the data 1OCR (Oxford Cambridge and RSA Examinations) The Triangle Building Shaftesbury Road Cambridge CB2 8EA [Show More]

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