Mathematics > EXAM > Exam (elaborations) AQA AS MATHEMATICS 7356/2 Paper 2 Mark scheme June 2020 Version: 1.0 Final Mark (All)

Exam (elaborations) AQA AS MATHEMATICS 7356/2 Paper 2 Mark scheme June 2020 Version: 1.0 Final Mark Scheme

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Where the question specifically requires a particular method to be used, we must usually see evidence of use of this method for any marks to be awarded. Where the answer can be reasonably obtained ... without showing working and it is very unlikely that the correct answer can be obtained by using an incorrect method, we must award full marks. However, the obvious penalty to students showing no working is that incorrect answers, however close, earn no marks. Where a question asks the student to state or write down a result, no method need be shown for full marks. Where the permitted calculator has functions which reasonably allow the solution of the question directly, the correct answer without working earns full marks, unless it is given to less than the degree of accuracy accepted in the mark scheme, when it gains no marks. Otherwise we require evidence of a correct method for any marks to be awarded. Diagrams Diagrams that have working on them should be treated like normal responses. If a diagram has been written on but the correct response is within the answer space, the work within the answer space should be marked. Working on diagrams that contradicts work within the answer space is not to be considered as choice but as working, and is not, therefore, penalised. Work erased or crossed out Erased or crossed out work that is still legible and has not been replaced should be marked. Erased or crossed out work that has been replaced can be ignored. Choice When a choice of answers and/or methods is given and the student has not clearly indicated which answer they want to be marked, mark positively, awarding marks for all of the student's best attempts. Withhold marks for final accuracy and conclusions if there are conflicting complete answers or when an incorrect solution (or part thereof) is referred to in the final answer. Q Marking Instructions AO Marks Typical Solution 1 Circles correct answer 1.1b B1 1 5 √?2 Total 1 Q Marking Instructions AO Marks Typical Solution 2 Ticks correct box 1.1b B1 –1 < y < 0 Total 1 Q Marking Instructions AO Marks Typical Solution 3 Differentiates once, at least one term correct 1.1a M1 ?? 2 1 = 12?3 − − ?? ?2 4 ?2? = 2 4 ??2 36x + ?3 Differentiates twice, both powers of x correct at least one coefficient correct (ACF) 1.1a M1 Condone one extra term from error differentiating − ? twice 4 Obtains completely correct expression with no errors 1.1b A1 Total 3 Q Marking Instructions AO Marks Typical Solution 4 Uses substitution cos2x = 1 – sin2 x in any form 1.2 B1 9sin2x – 6sinx + (1 – sin2x) = 0 8sin2x – 6sinx + 1 = 0 (4sinx – 1)(2sinx – 1) sin x = ¼ sin x = ½ 14°, 30°, 150°, 166° Solves ‘their’ quadratic to obtain two values for sin x 1.1a M1 Finds two correct solutions for x 1.1b A1 Finds all four solutions for x and no extras (condone 14.5, 165.5 AWRT) 1.1b A1 Total 4 ....................................................CONTINUED................................................ [Show More]

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