Statistics > QUESTIONS & ANSWERS > STAT200/STAT 200 Week 4 Homework Problems (summer 2021/22) complete solutions. (All)

STAT200/STAT 200 Week 4 Homework Problems (summer 2021/22) complete solutions.

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STAT 200 Week 4 Homework Problems 6.1.2 1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during peak rush hour periods of eight minutes ("2012 annual report," 2012). a.) State the random variable. X= waiting time during peak hours b.) Find the height of this uniform distribution. 1 8−0 =0.125 c.) Find the probability of waiting between four and five minutes. P(4< X<5)=(5−4)∗0.125=0.125 d.) Find the probability of waiting between three and eight minutes. P(3< X<8)=(8−3)∗0.125=0.625 e.) Find the probability of waiting five minutes exactly. P( x=5)=0∗0.125=.0000 6.3.2 Find the z-score corresponding to the given area. Remember, z is distributed as the standard normal distribution with mean of   0 and standard deviation   1 . a.) The area to the left of z is 15%. z-score = -1.036 b.) The area to the right of z is 65%. z-score = -0.385 c.) The area to the left of z is 10%. z-score = -1.282 d.) The area to the right of z is 5%. z-score = 1.645 This study source was downloaded by 100000831988016 from CourseHero.com on 04-05-2022 13:01:20 GMT -05:00 https://www.coursehero.com/file/39597120/STAT-200-Week-4-Homework-Problems-docx/ e.) The area between z and z is 95%. (Hint draw a picture and figure out the area to the left of the z .) z-score = 1.960 and -1.960 f.) The area between z and z is 99%. z-score = 2.576 and -2.576 6.3.4 According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998). Assume that blood pressure is normally distributed. a.) State the random variable. X = the blood pressure of the people in China b.) Find the probability that a person in China has blood pressure of 135 mmHg or more. P( x ≥135 )=P(z≥ 135−128 23 ) ¿ P( z ≥0.30)=1−P(z<0.30)=1−0.6179 = 0.3821 c.) Find the probability that a person in China has blood pressure of 141 mmHg or less. P( x ≤141)=P( z≤ 141−128 23 ) ¿ P(z≤0.565) =0.7157 d.) Find the probability that a person in China has blood pressure between 120 and 125 mmHg. P(120< x<125 )=P( 120−128 23 [Show More]

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