GCSE (9-1) Mathematics
Component 2
Grades 1-4 Practice Materials (Set 1)
Qualification
Accredited
GCSE (9-1)
MATHEMATICS
Practice Materials
Grades 1-4 Practice Materials
Set 1, Component 2
Version 1
J560
For
...
GCSE (9-1) Mathematics
Component 2
Grades 1-4 Practice Materials (Set 1)
Qualification
Accredited
GCSE (9-1)
MATHEMATICS
Practice Materials
Grades 1-4 Practice Materials
Set 1, Component 2
Version 1
J560
For first teaching in 2015
www.ocr.org.uk/mathsGCSE (9-1) Mathematics Grades 1-4 Practice Materials
© OCR 2020
Introduction
These practice materials can be used to support
foundation students who are targeting grades 1-4. They
are comprised of questions taken from previous series.
Mark schemes are included and can be found towards the
back of each set of materials.
Please remember to omit the mark schemes when
distributing the question pages to your students.
To see additional GCSE (9-1) Mathematics resources,
please visit: https://www.ocr.org.uk/qualifications/gcse/
mathematics-j560-from-2015/planning-and-teaching/
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convert PDF to Word (search for pdf to word converter).Grades 1-4 Practice Materials
1
GCSE (9-1) Mathematics
© OCR 2020
GCSE (9-1) Mathematics
Component 2
Grades 1-4 Practice Materials (Set 1)
Time allowed: 45 minutes
Name
50.
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15GCSE (9-1) Mathematics Grades 1-4 Practice Materials
11 © OCR 2020
Component 2 – Mark scheme
Types of marks:
• M marks are for using a correct method and are not lost for purely numerical errors.
• A marks are for an accurate answer and depend on preceding M (method) marks. Therefore M0 A1 cannot be awarded.
• B marks are independent of M (method) marks and are for a correct final answer, a partially correct answer, or a correct intermediate stage.
• SC marks are for special cases that are worthy of some credit.
The following abbreviations are commonly found in GCSE Mathematics mark schemes.
• cao means correct answer only.
• figs 237, for example, means any answer with only these digits. You should ignore leading or trailing zeros and any decimal point e.g. 237000, 2.37, 2.370,
0.00237 would be acceptable but 23070 or 2374 would not.
• isw means ignore subsequent working (after correct answer obtained).
• nfww means not from wrong working.
• oe means or equivalent.
• rot means rounded or truncated.
• seen means that you should award the mark if that number/expression is seen anywhere in the answer space, including the answer line, even if it is not in the
method leading to the final answer.
• soi means seen or implied.GCSE (9-1) Mathematics Grades 1-4 Practice Materials
12 © OCR 2020
Question Answer Marks Part marks and guidance
1 (a) 1 1 Condone 3
(b) 4 1
(c) Isosceles 1 Ignore spelling providing intention is clear
2 100 gram packet with a correct comparison isw 3 M1 for correctly finding the cost of 1 gram, 25
grams, 100 grams or other amount suitable for
comparison
M1 for attempting to find the cost of the same
amount of tea for each packet weight (e.g. 25
grams or 100 grams) evaluation does not need
to be correct
e.g. 100g of 25g pkt costs [£]4.2[0] e.g. 25g of
100g pkt costs [£]1.04 other comparisons must
be correct to 3sf or better
Or for attempt to fnd two values of grams per
pound or grams per pence
3 0 and 5 3 B1 for one correct
M1 for putting times in order isw Given values or their 9 or their 10 values
e.g. 0, 0, 2, 2, 6, 7, 7, 9
4 (a) (i) 13 1 Ignore subsequent terms
(ii) 128 1 Ignore subsequent terms
(b) (i) 15 11 1
(ii) 38 193 1
(c) 18 – 3n oe 2 M1 for –3n + k oe or for mn + 18 oe (m ≠ 0) For 2 or M1, condone e.g. n = 18 – 3n
For 2 or M1, condone use of other variable
instead of n
5 (a) 4p 1
(b) 5j – 2k 2 B1 for 5j or – 2k in final answer
6 (a) Tangent 1 Ignore spelling providing intention is clear
(b) Segment 1 Ignore spelling providing intention is clear
7 12 3 M2 for 420 ÷ 7 ÷ 5 or 420 ÷ 35
Or M1 for 420 ÷ 7 soi or 420 ÷ 5 soi
Condone 12.0, 12.00
8 (a) 3x2 + 6xy final answer 2 B1 for 3x2 or 6xy seen Condone 6yx
Do not accept e.g. 6 × x × y
(b) 4 1
9 (a) 7 ¼ oe 1 Accept e.g. isw
Do not accept e.g. 6
(b) 36 2 M1 for 63 ÷ 7 soi Implied by [ of 63] = 9
not enough for M1 without 9 or division sign
or bus stop e.g. 7)63
17
58
8
54
63
7GCSE (9-1) Mathematics Grades 1-4 Practice Materials
13 © OCR 2020
Question Answer Marks Part marks and guidance
10 (a) 6 1
(b) oe 1 Condone correct probability and unlikely for 1
mark
Accept [0].3818 to [0].382 or 38.18% to 38.2%
but not ratio or in words
(c) oe 1 Condone correct probability and likely for 1
mark
Accept [0].509 to [0].51 or 50.9% to 51% but
not ratio or in words
11 2 × 5 × 72 oe 2 B1 for only 2, 5 and 7 identified
Or M1 for any correct factor pair of 490
Condone inclusion of 1 for B1
Not 1 and 490
12 Correct enlargement (6, 3) (12, 3) (12, 9) (9, 12)
(6, 9)
3 B2 for correct enlargement incorrect centre or
enlargement scale factor 2 from correct centre
Or M1 for 3 points correctly plotted
Condone good freehand
13 (a) Point (0.8, 120) indicated 1
(b) No oe and
Correct supporting value(s) and justification
2 B1 for 200 to 260 visitors expected
or about 0 to 1mm and 320
or line of best fit
or negative trend/correlation
or markings in relevant region above 2mm
Justifcation includes reference to line of
best ft (drawn or not) or trend or negative
correlation or markings in relevant region
above 2mm or surrounding values
See below
(c) Outside range of data [collected] 1 Accept “The data (or diagram) only goes to 5.5
(or 6)” oe
Do not accept
“By 6 to 7 it would give no visitors” oe
There is no data around 9mm oe
The line of best ft does not reach 9mm oe
Condone “[Because] there would be a negative
number of people”
See below
14 1.25 3 B2 for 125 [cm] oe seen or ans figs 125
OR
M1 for 4 ft 2 in = 50 [inches] soi
M1 for their 50 × 2.5 soi Condone e.g. 48 for their 50
21
55
28
55GCSE (9-1) Mathematics Grades 1-4 Practice Materials
14 © OCR 2020
Question Answer Marks Part marks and guidance
15 (a) When multiplying [12.4] by 10, Nathan has not
moved the figures to the left [he has just added
a 0]
285.2
1 2
Accept 12.4 × 10 = 124 not 12.40
M1 for 12.4 × 20 = 248
or 124 × 2 = 248
Condone he has not moved the decimal point
to the right soi
Accept reference to either frst or second line
of working
See below
Accept 248 seen
If 12.4 × 23 is worked out using grid method,
allow M1 if no more than one error
If other long multiplication method used, allow
M1 if not more than one arithmetic slip but M0
if error in place value
(b) 8.60 3 M2 for 6.45 × 4 ÷ 3 oe
Or M1 for 6.45 × 4 oe or 25.8[0] seenGCSE (9-1) Mathematics Grades 1-4 Practice Materials
15 © OCR 2020
Exemplar responses for Q13(b)
Response Mark
(Line drawn on graph) No, following the scatter diagram points there would be an estimate of around
240 visitors
Take “following the scatter diagram points” refers to the line and a supporting value
2
No, we expect 250 (reference to line or markings drawn) 2
No, a line of best fit would show 250 (no line) 2
No, 0-1mm shows 320 but we would expect less as it is decreases/negative trend 2
No, (point below 2mm and point above 2mm stated) so there is a negative trend 2
No as with 1mm rain it's 280 visitors so with 2mm you should get around 245
B1 for 245 expected at 2mm but no reference to trend
1
Having drawn a line of best fit the scatter diagram wouldn’t support this as it’s too big a number
No explicit supporting value used
1
No, by looking at the diagram you would expect about 240
Supporting value in range but no justification
1
No because with 1mm there’s less than 320 visitors
1mm and 320 are the supporting values but no reference to trend
1
No because there were 320 visitors on a day with 0mm rainfall
0mm and 320 are the supporting values but no reference to trend
1
No we expect 250 (nothing else) 1
No, 0-1mm shows 320 1
No, 320 is for 1mm 1
No, negative trend 1
No, (point below 2mm and point above 2mm stated) 1
The scatter diagram doesn’t support his statement as there isn’t any rainfall that is 2mm
No supporting value
0
No it doesn’t because when the rainfall was 2mm he didn’t have any visitors
Wrong
0
The closest amount of visitors to 2mm of rainfall is 290
An estimate that is out of range and is probably referring to the nearest point plotted. No reference to
trend
0
No, as on a day with 1mm there are fewer customers 0
Yes … 0GCSE (9-1) Mathematics Grades 1-4 Practice Materials
16 © OCR 2020
Exemplar responses for Q13(c)
Response Mark
Outside range of data collected
Perfect!!
1
Because there is no data to show above 6mm of rainfall
Equivalent answer
1
Because the values of 7 and 8mm are not plotted, therefore it would be hard to estimate 9mm
Similar to “no data around 9mm”
0
No record of any visitors are shown at 9mm of rainfall. Visitors stop coming when it hits 6mm of rainfall
Equivalent to “no data for 9mm”
0
Because there is not enough data to estimate the amount of visitors for 9mm of rainfall
Does not say “no data beyond 5.5 (or 6) mm”
0
We don’t have the data to do a line of best fit
Wrong
0
There is nothing recorded
Wrong
0
You can’t plot this data the graph isn’t big enough
Wrong
0
Because that would create an outlier or anomalous piece of data
Maybe but wrong
0
It wouldn’t be on the line
Wrong
0
There would be under 50 visitors so it would be hard to get an accurate number
Wrong
0
Because the experiment was only tested for 10 days, you would need to have more evidence to
estimate how many visitors would come on 9mm rainfall
Probably correct but has missed the point that THESE data do not extend beyond 5.5mm
0
Because the rain might be too heavy for visitors to come
True but not answering the question
0GCSE (9-1) Mathematics Grades 1-4 Practice Materials
17 © OCR 2020
Exemplar responses for Q15(a)
Response Mark
For 10 × 12.4 Nathan has only times by 1. For 20 × 12.4 he has only times by 2. 10 × 12.4 = 124
Accept identifying that he has timesed by 1 instead of 10, or by 2 instead of 20
1
10 × 12.4 is not 12.40 it is 124. He didn’t add the 0s onto the numbers
10 × 124 is not 12.40 it is 124 scores 1, ignore the rest of the explanation because it is unclear
rather than being incorrect
1
He added 0 to 12.4
Explains what he has done wrong
1
He does not move the decimal place when he × by 10 so it should have been 124.0
Doesn’t need to say where
1
Nathan has got the place value wrong on frst answer
They have correctly identifed that the error is in the place value
1
10 × 12.4 = 124 so 20 × 12.4 is wrong
Allow identifcation of error in second line
1
Instead of moving the decimal place to the right he just added a zero to the end of the number
and instead of multiplying he added
Ignore fnal part of statement
1
He hasn’t multiplied it he just added a zero that makes no difference
Error identifed and ‘makes no difference’ explains error
1
He said that 20 × 12.4 is 24.80 when it is 248 which means the answer is 285.2
Accept reference to second line of working
1
When Nathan done 10 × 12.4 it should equal 124
10 × 12.4 = 124 is not enough. ‘It should equal 124’ is just about enough to identify the error
1BOD
When he multiplied by 10 he didn’t remove the decimal place and same when he multiplied by 20
Multiplying by 10 isn’t the same as removing the decimal place
0
Nathan kept the decimal in. When calculating a sum with a decimal you take it out as you do the
sum then put it back at the end
Too vague
0
Nathan has divided the 12.4 rather than moving the decimal point to the right (positive/
multiplying)
Moving the decimal point to the right would score 1, but we can’t ignore the rest of the
explanation because it is incorrect rather than unclear
0
12.40 is wrong
Identifes error but doesn’t explain
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