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University of Texas - PHY 58235HW 25

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Morby, Grant { Homework 25 { Due: Apr 3 2006, noon { Inst: Drummond 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page { flnd all choices ... before answering. The due time is Central time. 001 (part 1 of 3) 10 points A string is wrapped around the stem of a YoYo which has a mass M and a moment of inertia I about its center axis. The radius of the stem is r1 and the radius of the disk is r2. Denote the tension of the string T and the descending acceleration a. h r2 r1 M ! The correct torque equation is given by 1. T r1 = 2 a I r1 + r2 : 2. T r1 + r2 2 = 2 a I r2 : 3. T r1 + r2 2 = 2 a I r2 ¡ r1 : 4. T r1 = a I r1 : 5. T r1 + r2 2 = 2 a I r1 : 6. T r2 ¡ r1 2 = 2 a I r1 + r2 : 7. T r1 + r2 2 = 2 a I r1 + r2 : 8. T r2 = a I r2 : 9. T r2 = 2 a I r1 + r2 : 002 (part 2 of 3) 10 points The correct vertical force equation is given by 1. M g + T = M a : 2. M g ¡ T = M a : 3. T ¡ M g = M a : 003 (part 3 of 3) 10 points Release the Yo-Yo from rest. It reaches a center of mass speed v when it falls for a height ¢h. Using the same notation as in the previous questions, the correct work-energy equation is given by 1. 1 2 M v2 = 1 2 Iv2 : 2. 1 2 M v2 = 1 2 I µrv1¶2 : 3. M g ¢h = 1 2 I µrv1¶2 : 4. M g ¢h = 1 2 M v2 : 5. M g ¢h = 1 2 M v2 + 1 2 I µrv2¶2 : 6. M g ¢h = 1 2 M v2 + 1 2 I µrv1¶2 : 7. M g ¢h = 1 2 I µrv2¶2 : 8. 1 2 M v2 = 1 2 I µrv2¶2 : 004 (part 1 of 2) 10 points A hollow cylinder has length a 1:9 m, mass 0:8 kg, and radius 0:3 m. The cylinder is free to rotate about a vertical axis that passes through its center and is perpendicular to the cylinder’s axis. Inside the cylinder are two masses of 0:2 kg each, attached to springs of spring constant k and unstretched lengths 0:2 m. The inside walls of the cylinder are frictionless. 1:9 m 0:4 m 0:2 kg 0:2 kg 0:8 kg Determine the value of the spring constant k if the masses are located 0:6 m from the cenhttps://www.coursehero.com/file/1652338/HW-25/ This study resource was shared via Course [Show More]

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