Mathematics > QUESTIONS & ANSWERS > MATH 1280 Introduction to Statistics - Term 4, 2018-2019 University of Phoenix - EDUCATION MTE 531pd (All)

MATH 1280 Introduction to Statistics - Term 4, 2018-2019 University of Phoenix - EDUCATION MTE 531pdf (1).

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Started on Saturday, 1 June 2019, 11:15 PM State Finished Completed on Saturday, 1 June 2019, 11:33 PM Time taken 17 mins 51 secs Marks 16.00/16.00 Grade 100.00 out of 100.00 Recall that the pop... ulation average of the heights in the Õle "pop1.csv" is μ = 170.035. Using simulations we found that the probability of the sample average of the height falling within 1 centimeter of the population average is approximately equal to 0.626. From the simulations we also got that the standard deviation of the sample average is (approximately) equal to 1.122. In the next 3 questions you are asked to apply the Normal approximation to the distribution of the sample average using this information. The answer may be rounded up to 3 decimal places of the actual value: Using the Normal approximation, the probability that sample average of the heights falls within 1 centimeter of the population average is Answer: 0.6272133 The correct answer is: 0.6272133 Using the Normal approximation we get that the central region that contains 95% of the distribution of the sample average is of the form 170.035 ± z · 1.122. The value of z is Answer: 1.959964 The correct answer is: 1.959964 MATH 1280 Introduction to Statistics - Term 4, 2018-2019 https://www.coursehero.com/file/42565853/Graded-Quiz-Unit-8pdf/ This study resource was https://www.coursehero.com/file/49539924/pdf-1pdf/ shared via CourseHero.com This study resource was shared via CourseHero.com6/8/2019 Graded Quiz Unit 8 https://my.uopeople.edu/mod/quiz/review.php?attempt=1904843&cmid=174843 2/7 Question 3 Correct Mark 1.00 out of 1.00 Question 4 Correct Mark 1.00 out of 1.00 Information Using the Normal approximation, the probability that sample average of the heights is less than 168 is Answer: 0.0351 The correct answer is: 0.03486 According to the Internal Revenue Service, the average length of time for an individual to complete (record keep, learn, prepare, copy, assemble and send) IRS Form 1040 is 10.53 hours (without any attached schedules). The distribution is unknown. Let us assume that the standard deviation is 2 hours. Suppose we randomly sample 36 taxpayers and compute their average time to completing the forms. Then the probability that the average is more than 11 hours is approximately equal to (The answer may be rounded up to 3 decimal places of the actual value.) [Show More]

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