Management > QUESTIONS & ANSWERS > University of Louisville - MGT 6203HW3_MGT 6203 (All)
University of Louisville - MGT 6203HW3_MGT 6203
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- kag[(kag$Spent == 0),] #### Find the ad with the most impressions: max(zeroCPC$Impressions) ## [1] 24362 #### Use that max impressions to find the ad_id: zeroCPC[match(max(zeroCPC$Impressions),... zeroCPC$Impressions),] ## ad_id xyz_campaign_id fb_campaign_id age gender interest Impressions ## 521 1121094 1178 144531 30-34 M 10 24362 ## Clicks Spent Total_Conversion Approved_Conversion ## 521 0 0 1 1 The ad_id 1121094 has the lowest CPC of [undefined, because we’re dividing by 0] and has 24,362 impressions. ________________________________________ Q.1.B: What campaign (provide campaign_id as the answer) had spent least efficiently on brand awareness on an average? #### Determine cpm: cpm <- kag$Spent / kag$Impressions * 1000 #### Split data into different groups based on xyz_campaign_id: id_916 <- kag[1:54,] id_936 <- kag[55:518,] id_1178 <- kag[519:1143, [Show More]
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