Physics > QUESTIONS & ANSWERS > Physics 30: Assignment 10, Divided into 2 parts:Part One: Electromagnetic Radiation and Part Two: Th (All)

Physics 30: Assignment 10, Divided into 2 parts:Part One: Electromagnetic Radiation and Part Two: The Speed of Light. With Verified answers

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ASSIGNMENT 10 Part One: Electromagnetic Radiation Part One of this assignment is worth 11 marks. The value of each question is noted in parentheses in the left margin. Note: The answer areas will e ... xpand to fit the length of your response. 1. (1) Medical technologies related to imaging and cancer treatment use high-frequency EMR. a. Explain why high frequency EMR is harmful. Answer: High frequency EMR is harmful due to its high energy potential. In the equation E=hf, where E is energy, h is the Planck’s constant and f is the frequency of the EMR, the greater the frequency, the greater its energy. When the energy of an EMR is higher, it has a greater ionizing power, causing it to be able to penetrate stronger barriers. Most types of EMR are easily blocked by the skin, however, EMR with higher frequencies than visible light (ultraviolet, X-ray, gamma and cosmic radiation) are able to penetrate very strong surfaces. Some types of EMR can cause permanent skin damage while others may cause internal problems, radiation sickness or even death. (1) b. What precautions should medical personnel take when working with these types of technologies? Answer: Medical personnel should wear protective (often lead encased) aprons and limit their exposure to such technology. Recently, medical personnel will exit the room and use a digital camera with robotic functions in order to take pictures that involve X-rays and other high-frequency EMRs. This strongly lowers their exposure to high-frequency EMR. 2. A student measures the period of an electromagnetic wave as 3.64 x 10-15 s. (1) a. What is the frequency of the wave? Answer: T= 3.64x10-15s T= 1/f f=1/T f= 1 3.64 x 10−15 s f= 2.74725x1014 Hz f= 2.75x1014 Hz (1) b. What is the wavelength of the wave? Answer: f= 2.75x1014 Hz v= 3.00x108 m/s Part Two: The Speed of Light Part Two of this assignment is worth 20 marks. The value of each question is noted in the left margin in parenthesis. Note: The answer areas will expand to fit the length of your response. (3) 1. If you know Earth’s orbital diameter and can measure the difference in eclipse times for Jupiter’s moon, Io, you can calculate the speed of light. If an eclipse of Io occurred 24 min later than expected and Earth’s orbital diameter is 3.0 x 1011 m, what is the speed of light? Answer: t= 24 min= 1440s d= 3.0x1011m v= dt v= 3.0 x 1011m 1440 s v= 2.1x108 m/s (3) 2. As shown below, a rotating mirror with 16 sides was used to measure the time it took light to travel 3.5 km to a concave mirror and back. At what frequency did the rotating mirror need to turn such that it made 1/16th of a rotation in the time it took light to travel the 3.5 km and back again? [Show More]

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