Physics > QUESTIONS & ANSWERS > Calorimetry Lab SE (All)
Vocabulary: calorie, calorimeter, joule, specific heat capacity Prior Knowledge Questions (Do these BEFORE using the Gizmo.) 1. The Latin word calor means “heat,” and meter comes from th ... e Greek word meaning “to measure.” What do you think a calorimeter does? a device used to measure the heat transferred from a substance to another substance 2. Where have you heard the word calorie before? What do you think a calorie is? amount of energy that changes temperature Gizmo Warm-up A calorimeter is an insulated container filled with a liquid, usually water. When a hot object is placed in the calorimeter, heat energy is transferred from the object to the water and the water heats up. Calorimeters can be used to find a substance’s specific heat capacity. You will use the Calorimetry Lab Gizmo™ to determine the specific heat capacities of various substances. 1. On the SIMULATION pane, select Copper. Use the slider to set its Mass to 200 g. Set the Water mass to 200 g. Check that the Water temp is set to 30.0 °C and the copper’s Temp is 90 °C. Select the GRAPH tab, and click Play ( ). A. What was the Final temperature of the copper and the water? 34.96 C B. How much did the temperature of the copper change? 55.04 C C. How much did the temperature of the water change? 4.96 C 2. Specific heat capacity can be described as a substance’s resistance to temperature changes. Which substance has a greater specific heat capacity, copper or water? Explain. the water has the greater specific heat because it doesn't change a lot Question: What factors determine how heat energy transfers between objects? 1. Predict: In the Gizmo warm-up, you saw how 200 g of 90 °C copper transfers heat to 200 g of 30.0 °C water. A. How do you think increasing the water’s mass would affect the final temperature? the final temperature will decrease while the water's mass increases B. How do you think decreasing the copper’s mass would affect the final temperature? decreasing the cooper's mass will decrease the final temperature ....................................................Continued................................... [Show More]
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