Physics > TEST BANKS > TEST BANK FOR PHYSICS 1710. COMPLETE GUIDE FOR EXAM PREPARATION. GRADED A. (All)

TEST BANK FOR PHYSICS 1710. COMPLETE GUIDE FOR EXAM PREPARATION. GRADED A.

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Practice Homework Chapter 5 Solutions – Weathers – (17101) 1 This print-out should have 65 questions. Multiple-choice questions may continue on the next column or page – find all choices bef ... ore answering. 001 (part 1 of 8) 10.0 points Assume you are on a planet similar to Earth where the acceleration of gravity is approximately 10 m/s2 and the positive directions for displacement, velocity, and acceleration are upward. At time t = 0 s, an elevator is at a displacement of x = 0 m with a velocity of v = 0 m/s. A student whose normal weight is 400 N stands on a scale in an elevator and records the scale reading as a function of time. The data are shown in the graph. 0 5 10 15 20 0 200 400 600 800 time (s) Scale Reading (N) In which direction does the force due to the scale act on the student? 1. backward 2. right 3. up correct 4. The net force on the student is zero, so the force the scale exerts on the student has no direction. 5. forward 6. down 7. left Explanation: The scale exerts a normal force (Scale Reading Fs), opposite to the force of gravity m g; i.e., upward. 002 (part 2 of 8) 10.0 points What is the mass of the student? 1. m ≈ 70 kg 2. m ≈ 30 kg 3. m ≈ 10 kg 4. m ≈ 60 kg 5. m ≈ 40 kg correct 6. m ≈ 80 kg 7. m ≈ 50 kg 8. m ≈ 90 kg 9. m ≈ 20 kg Explanation: Since W = m g, we have m = W g = 400 N 10 m/s2 = 40 kg . 003 (part 3 of 8) 10.0 points Calculate the acceleration of the elevator during the fourth 5 s interval (from 15 s to 20 s). Correct answer: 5 m/s2. Explanation: The net force Fnet on the student is Fnet = Fs − 400 N = m a , so a = Fs − 400 N m . The accelerations during the 5-second intervals are a0→5 = 400 N − 400 N 40 k [Show More]

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