Engineering > QUESTIONS & ANSWERS > TOBB University of Economics and Technology MAK 206 Ch04-verified by experts-ALL ANSWERS CORRECT (All)

TOBB University of Economics and Technology MAK 206 Ch04-verified by experts-ALL ANSWERS CORRECT

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The composite A-36 steel bar shown in Fig. 4–6a is made from two segments, AB and BD, having cross-sectional areas of AAB 600 mm2 and ABD 1200 mm2. Determine the vertical displacement of end A... and the displacement of B relative to C. 20 kN 20 kN 75 kN 20 kN 20 kN 75 kN = 75 kN 75 kN P AB PBC = 35 kN PCD = 45 kN (b) 40 kN 40 kN 20 kN 20 kN 40 kN 40 kN 75 kN 0.75 m 1 m 0.5 m A B C D (a) P (kN) x (m) 35 75 0 1.0 1.75 –45 2.25 (c) E X A M P L E 4.1 Solution Internal Force. Due to the application of the external loadings, the internal axial forces in regions AB, BC, and CD will all be different. These forces are obtained by applying the method of sections and the equation of vertical force equilibrium as shown in Fig. 4–6b. This variation is plotted in Fig. 4–6c. Displacement. From the inside back cover, Est 210(103) MPa. Using the sign convention, i.e., the internal tensile forces are positive and the compressive forces are negative, the vertical displacement of A relative to the fixed support D is Ans. Since the result is positive, the bar elongates and so the displacement at A is upward. Applying Eq. 4–2 between points B and C, we obtain, Ans. Here B moves away from C, since the segment elongates. [Show More]

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