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Chemsheets-A2-1014-Thermodynamics-booklet-ANS.

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Ex1 ΔH = [Sum of ΔHf products] – [Sum ΔHf reactants] = [ -394 + 2(-286) ] – [–75 + 0] = –891 kJ mol-1 Ex2 ΔH = [Sum of ΔHf products] – [Sum ΔHf reactants] -2877 = [ 4(-394) + 5(-28 ... 6) ] – [ΔfH + 0] ΔfH = 2877 + 4(-394) + 5(-286) = –129 kJ mol-1 PAGE 5 EXAMPLES C(s) + 2 H2(g) ΔH CH4(g) –890 –394 2(–286) Ex 1 CO2(g) + 2 H2O(l) ΔH – 890 = –394 + 2(–286) ΔH = –394 + 2(–286) + 890 = –76 kJ mol-1 [Show More]

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