Mathematics > QUESTIONS & ANSWERS > Summary BNU1501: Solutions for Assignment 03 For 2021 (All)

Summary BNU1501: Solutions for Assignment 03 For 2021

Document Content and Description Below

BNU1501 2019 Semester 02 Assignment 02 Solutions Here are our correct options to the assignment questions Q 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 A 2 4 1 3 2 3 1 2 3 4 3 2 4 1 3 Question 1 To conve... rt mixed fractions to improper fractions 3 4 7 Multiply the whole number part by the fraction’s denominator. 3 × 7 = 21 Add the product that to the numerator. 21 + 4 = 25 Then write the answer you got on step 2, on top of the denominator. 25 7 Option [2] Question 2 To convert an improper fraction to a mixed fraction: ??? ? Divide the numerator by the denominator. ??? ÷ ? = ??, 28571429 Multiply the answer’s whole number by the denominator: 14 × 7 = 98 Subtract the product from the original numerator to get the remainder: 100 – 98 = 2 Rewrite the improper fraction as a mixed fraction ??? = ?? ? ? ? Option [4]5 Question 3 The steps for finding the LCM of integers are ▪ Express each number as a product of prime powers. ▪ For each prime factor choose the prime power with largest exponent among all numbers. ▪ The LCM is the product of the chosen prime powers. Let us express each number as prime factors: 9 = 3 × 3 = 32 8 = 2 × 2 × 2 = 23 6 = 2 × 3 The prime factors are 2 and 3 with the highest power ones being 23 and 32 The LCM is the product of the chosen prime powers. That is 23×32 = ?? Option [1] Question 4 The steps of finding the LCM for variables are similar to that of integers, but much easier because the variables are prime factored already. ?2?? ; ??? ; ??3 The biggest power of ? is 2, the biggest power of ? is 1 and the biggest power of ? is 3. The LCM is thus, ????� [Show More]

Last updated: 2 years ago

Preview 1 out of 12 pages

Buy Now

Instant download

We Accept: