Prior Knowledge Questions (Do these BEFORE using the Gizmo.)
1. The Latin word calor means “heat,” and meter comes from the Greek word meaning “to
measure.” What do you think a calorimeter does? < Measures heat >
2. W
...
Prior Knowledge Questions (Do these BEFORE using the Gizmo.)
1. The Latin word calor means “heat,” and meter comes from the Greek word meaning “to
measure.” What do you think a calorimeter does? < Measures heat >
2. Where have you heard the word calorie before? What do you think a calorie is? < unit of
measurement for heat. >
Gizmo Warm-up
A calorimeter is an insulated container filled with a liquid,
usually water. When a hot object is placed in the calorimeter,
heat energy is transferred from the object to the water and the
water heats up.
Calorimeters can be used to find a substance’s specific heat
capacity. You will use the Calorimetry Lab Gizmo™ to
determine the specific heat capacities of various substances.
1. On the SIMULATION pane, select Copper. Use the slider to set its Mass to 200 g. Set the
Water mass to 200 g. Check that the Water temp is set to 30.0 °C and the copper’s Temp
is 90 °C. Select the GRAPH tab, and click Play ( ).
A. What was the Final temperature of the copper and the water? < 30.54
>
B. How much did the temperature of the copper change? < 60 >
C. How much did the temperature of the water change? < 5 >
2. Specific heat capacity can be described as a substance’s resistance to temperature
changes. Which substance has a greater specific heat capacity, copper or water? Explain.
< Copper because it’s a better heat conductor than water. >
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
Activity A:
Heat transfer
Get the Gizmo ready:
Click Reset ( ).
Question: What factors determine how heat energy transfers between objects?
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
1. Predict: In the Gizmo warm-up, you saw how 200 g of 90 °C copper transfers heat to 200 g
of 30.0 °C water.
A. How do you think increasing the water’s mass would affect the final temperature?
< it should bring the temp down >
B. How do you think decreasing the copper’s mass would affect the final temperature?
< it will bring it down>
C. How do you think increasing or decreasing the copper’s initial temperature would
affect the final temperature? < increasing will increase final temp and decreasing
will lower final temp >
2. Collect data: Use the Gizmo to determine the final temperature for each set-up listed below.
Record your results in the tables. In the first table, you experiment with changing the water’s
mass. In the second table, you change the copper’s mass. In the third table, you change the
initial temperature of the copper. The first row of each table has been completed for you.
Copper Water Final Temp.
(°C) Initial Temp. (°C) Mass (g) Initial Temp. (°C) Mass (g)
3.
90 °C 200 g 30.0 °C 200 g 34.96 °C
90 °C 200 g 30.0 °C 2,000 g < 30.05 >
4.
90 °C 200 g 30.0 °C 200 g 34.96 °C
90 °C 20 g 30.0 °C 200 g < 30.54 >
5.
90 °C 200 g 30.0 °C 200 g 34.96 °C
100 °C 200 g 30.0 °C 200 g < 35.79 >
50 °C 200 g 30.0 °C 200 g < 31.65 >
3. Analyze: For each factor listed in the chart below, explain how the final temperature was
changed and why you think that change occurred.
A. What was the effect of increasing the water’s mass? < decreased >
B. What was the effect of decreasing the copper’s mass? < decreased >
C. What was the effect of changing the initial temperature of the copper? < increase in
final temp when increased initial temp and vice versa. >
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
4. Draw conclusions: The amount that the water’s temperature increases depends
on the mass of the water and the amount of heat energy in the copper.
A. How does changing the initial mass of the copper affect how much heat
energy it has? < the more copper you have will increase the
temperature and lowering it will decrease it because the less copper
means less heat energy. >
B. How does changing the initial temperature of the copper affect how much
heat energy it has? < the more copper means more heat. less means
less heat. >
5. Apply: Many gyms and health clubs have steam saunas, which are small steamfilled rooms. Traditionally, steam saunas have a container of heated rocks. A
small ladle of water is poured on the rocks in order to make the steam.
A. Use what you have learned so far about heat transfer to explain how hot
rocks can be used to make steam? < the hot rocks release heat as
water touches them. The rocks are very hot, and the water
evaporates once both make contact. >
B. Why do you think only a small ladle-full of water is poured on the rocks at
one time?
< to much water will cool the rocks and you won’t get any heat
releasing because the rocks will have lost all the heat due to all the
water poured on them. >
Activity B:
Specific heat
Get the Gizmo ready:
Click Reset.
Deselect Copper, and select Granite.
Question: How can you compare the specific heat capacities of various
substances?
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
1. Explain: How do you think you can use the calorimeter to compare the specific heat
capacities of the substances listed on the Gizmo? < Compare how much different
substances will heat up in the water. >
2. Predict: Which substance do you think will have the highest specific heat capacity? Why?
< Copper because it is a metal and its conductor >
3. Experiment: Use the Gizmo to determine the final temperature for each set-up listed below.
Record your results in the table. The first row has been completed for you.
Substance Substance initial
temp. (°C)
Substance
mass
Water initial
temp. (°C)
Water
mass
Final
temp. (°C)
Copper 90 °C 200 g 30.0 °C 200 g 34.96 °C
Granite 90 °C 200 g 30.0 °C 200 g < 39.59 >
Lead 90 °C 200 g 30.0 °C 200 g < 31.75 >
4. Analyze: Of the three substances, which caused the largest temperature change in the
water? What does this indicate about its relative specific heat capacity? < granite causes
the biggest change, so it has the most heat capacity >
5. Interpret: Remember that specific heat capacity is a measure of a substance’s resistance to
temperature change. The more resistant a substance is to temperature change, the higher is
its specific heat capacity.
Rank the three substances in order of their specific heat capacities, from highest to lowest.
< Granite, copper, lead >
6. Predict: How do you think the specific heat capacity of ice will compare to that of copper,
granite, and lead? < it will be lower. >
7. Experiment: Deselect Lead, and select Ice. Use the default values for Temp (-30 °C) and
Mass (50 g). Set the Water temp to 60 °C and the Water mass to 200 g. Click Play.
A. What was the final temperature? < 28.83 >
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
B. What do you think is happening when the ice line on the graph is at 0 °C
for a long period of time? Why do you think the line disappears after that?
< the ice will start to melt and the line disappears when the ice
completely melts >
C. How much of a temperature change did the water experience? < 31.17 >
D. How does this change in the water’s temperature compare to the change
caused by the other substances you tested? < the temperature change
was greater >
8. Extend your thinking: A lot of energy is needed to heat a substance with a high
specific heat capacity. However, even more energy is needed to cause a phase
change (such as the melting of ice). Click Reset. Set the ice’s Temp to -100 °C
and its Mass to 50 g. Set the Water temp to 50 °C and Water mass to 200 g.
Click Play.
A. What was the final temperature? < 13.39 >
B. Do you think all the ice melted? Explain. < yes the line had completely
disappeared>
C. Look at the GRAPH. The graph shows two separate stages: the heating of
the ice and then the melting of the ice. How much did the water’s
temperature change while the ice was heating? How much did it change
while the ice was melting?
< water temperature changed around -14 C while the ice was heating
and was about -22 C >
How did this experiment demonstrate ice’s high specific heat capacity? < While the
process was taking place the ice caused a greater change in the temp of the
water. >
Activity C:
Calculating
specific heat
Get the Gizmo ready:
Click Reset.
Introduction: The specific heat capacity of a substance is the amount of energy
needed to change the temperature of that substance by 1 °C. Specific heat capacity
can be calculated using the following equation:
q = mc∆T
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
In the equation q represents the amount of heat energy gained or lost (in joules), m
is the mass of the substance (in grams), c is the specific heat capacity of the
substance (in J/g °C), and ∆T is the temperature change of the substance (in °C).
Goal: Calculate the specific heat capacities of copper, granite, lead, and ice.
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
1. Solve: When you mix two substances, the heat gained by one substance is equal to the heat
lost by the other substance. Suppose you place 125 g of aluminum in a calorimeter with
1,000 g of water. The water changes temperature by 2 °C and the aluminum changes
temperature by –74.95 °C.
A. Water has a known specific heat capacity of 4.184 J/g °C. Use the
specific heat equation to find out how much heat energy the water gained (q).
< 1000g x 4.18 j/gC = 8368j/g C >
B. Assume that the heat energy gained by the water is equal to the heat
energy lost by the aluminum. Use the specific heat equation to solve for the specific
heat of aluminum. (Hint: Because heat energy is lost, the value of q is negative.)
< -8368 J/(125g x (-74.95C)= 0.839J/gC >
Aluminum’s accepted specific heat value is 0.900 J/g °C. Use this value to check your work.
2. Calculate: Use the Gizmo to mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C.
A. What is the final temperature? < 21.42 >
B. Calculate the temperature change of each substance by subtracting the initial
temperature from the final temperature.
∆Twater: < 1.42 > ∆Tcopper: < -78.58 >
C. How much heat energy (q) did the water gain? < 5941.28 >
D. Now solve for the specific heat (c) of copper: < .378 >
3. Calculate: Use the Gizmo to mix 200 g of granite at 100 °C with 1,000 g of water at 20 °C.
A. What is the final temperature? < 22.93 >
B. Calculate the temperature change of each substance by subtracting the initial
temperature from the final temperature.
∆Twater: < 2.93 > ∆Tgranite: < -77.07 >
C. How much heat energy (q) did the water gain? < 12 259.12 >
D. Now solve for the specific heat (c) of granite: < .795 >
E. Repeat steps A through D to find the specific heat (c) of lead: < .130 >
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:00
https://www.coursehero.com/file/33165429/TC10gizmodocx/
This study resource was
shared via CourseHero.com
4. Challenge: Use the specific heat capacity that you calculated for granite to determine how
many grams of granite at the initial temperature of 80 °C must mix with 3,000 g of water at
the initial temperature of 20 °C to result in a final system temperature of 20.45 °C. (Hint:
Start by calculating how much heat energy is needed to change the water’s temperature by
0.45 °C). Show your work. Use the Gizmo to check your answer.
3000g x 4.184j/g x 0.45 c= 5648j
.795j/g x -59.55C = -5648
Mass of granite= 119.31g
Mass of granite = < 119.31g >
5. Extend your thinking: In addition to calculating specific heat capacities, some calorimeters
can be used to determine how much energy is in food. The energy in food is usually
expressed in calories or kilocalories (Calories). A calorie is the amount of energy needed to
change the temperature of 1 g of water by 1 C. There are 1,000 calories in a Calorie.
A. How many joules are in 1 calorie? (The specific heat of water is 4.184 J/g °C.) <
4.184 j >
B. Suppose a snack bar is burned in a calorimeter and heats 2,000 g water by 20 °C.
How much heat energy was released? (Hint: Use the specific heat equation.) Give
your answer in both joules and calories.
< 167369 j and 40000 calories >
C. How many kilocalories (Calories) does the snack bar contain? < 40 >
This study source was downloaded by 100000796615030 from CourseHero.com on 07-07-2021 06:47:04 GMT -05:0
[Show More]
.png)
