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Embry-Riddle Aeronautical University PHS 250 Project

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Abstract Our group for physics 250 class, chose a challenge about an interstellar trip to the center of our galaxy. Our team will provide a qualitative and quantitative explanation of the scenario ... below. If you travel by starship to the center of the galaxy such that you arrive within a subjective human lifespan, how much radiation damage will you suffer from the interstellar vacuum? Your group’s solution to this problem needs to address the following, at a minimum: - Assume special relativity holds and ignores the problems of accelerating and decelerating the spacecraft. - At what point in the journey through the interstellar vacuum would you suffer too much radiation damage to go on? - How did you determine the amount of radiation damage? What equations did you need? What values did you use for the variables? How did you determine those values? The solution to this problem will be guided by text that explains the details of the solution to the problem.Thus giving support to the physical concepts that will be used to solve the problem, some concepts such as general relativity and the correlation between mass and energy. Fundamentals of the Problem In order to solve this problem we would need to evaluate a realistic timeline in which a human can travel such great distances. Then, we could begin to evaluate the external forces that would act on the human body, and present the challenges (whether or not they can be overcome). To achieve a rough estimate of the amount of radiation damage the trip will have on a human body, we must consider the amount of atoms the starship will come across and the radiation damage induced by each atom. As the first and given assumption we must consider the laws of special relativity hold and disregard whether the starship accelerates or decelerates. This will help to consider only a constant velocity, in this case close to the speed of light due to the great distances we must travel. For the second assumption we will consider hydrogen atoms as the base atom for our calculations. [Show More]

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