Statistics > QUESTIONS & ANSWERS > AMDM spring A3.docx (All)

AMDM spring A3.docx

Document Content and Description Below

QUESTION 1 A) State the null and alternative hypotheses relevant to the situation? The null hypothesis is the one to be tested and the alternative is everything else. Thus, in determining the valid... ity of the claim of the manufacturer the test is to be determined as to the mean of the claimed bulb hours is less than or equal to 5000 hours. The null hypothesis for the test H0 : μ>5000 hours The alternative hypothesis for the test H1 : μ≤ 5000 hours If the claim of the manufacturer is true that the Bulb will last for more than 5000 hours the null hypothesis will be correct and if proven otherwise by the sample of 70 bulbs the alternative hypothesis will be correct. B) n= 70 X´ hours=355910/70 = 5084.43 hours, SD=350 hours Significance level of 5%, therefore ∝ = 0.05. Confidence interval = +¿ t∝(n−1)∗(SD /√n) ´xhours ¿ 5084.43 +¿ t 0.05 (70−1)∗(350 / √70) ¿ 5084.43 +¿1.667∗41.83 ¿ 5084.43 +¿ ¿ 69.73 I.e. (5014.7,5154.16) is the confidence interval. Based on the above information, z0= x−μ s √n z0= 5084.43−5000 350 √70 = 4964.9 z0=4964.9 Because z0>z0.95 (4964.9>1.667), and hours falls outside the confidence interval (the interval: (5014.7, μ 5154.16) and the hours = 5000). μ Therefore, we can reject the null hypothesis H0 that the claim of the manufacturer that the bulb will last for more than 5000 hours And, we can assure that the H1 hypothesis is correct, that the findings of the quality control engineer has proven otherwise. C) n= 70 X´ hours=355910/70 = 5084.43 hours Rohit Biju Augustine Assignment 3 This study source was downloaded by 100000829219024 from CourseHero.com on 08-27-2021 20:45 [Show More]

Last updated: 2 years ago

Preview 1 out of 8 pages

Buy Now

Instant download

We Accept: