Glossary for Mark Schemes
These examinations are marked in such a way as to award positive achievement wherever possible. Thus,
for these papers, marks are awarded under various categories.
M Method marks are awarded
...
Glossary for Mark Schemes
These examinations are marked in such a way as to award positive achievement wherever possible. Thus,
for these papers, marks are awarded under various categories.
M Method marks are awarded for a correct method which could lead
to a correct answer.
A Accuracy marks are awarded when following on from a correct
method. It is not necessary to always see the method. This can be
implied.
B Marks awarded independent of method.
M Dep A method mark dependent on a previous method mark being
awarded.
BDep A mark that can only be awarded if a previous independent mark
has been awarded.
ft Follow through marks. Marks awarded following a mistake in an
earlier step.
SC Special case. Marks awarded within the scheme for a common
misinterpretation which has some mathematical worth.
oe Or equivalent. Accept answers that are equivalent.
eg, accept 0.5 as well as
12Practice Paper - Paper 1 - Set 2 - 8360/1 - AQA Level 2 Certificate in Further Mathematics
4
Paper 1 - Non-Calculator
Q Answer Mark Comments
1 6x2 5 B2 B1 For one term correct
2(a) 7n 3 B2 B1 For 7n ?
2(b) Their 7n 3 150 M1 oe Allow 7n 3 = 150
21 A1
Alt 2(b) Substitutes a value of n 20 M1 Works out 15 or more terms
21 A1
3 5x + k = 3 M1
3x k = 1 M1
8x = 4 M1
(x = ) 0.5 A1 oe
4 3a + 8 = 2 or –3 + 4 = b M1 Sight of b = 1 or a = 2 earns this mark
3a + 8 = 2 and –3 + 4 = b M1
a = –2 and b = 1 A1
5(a)
12
4
or
13
M1 oe
5(b)
y7
=
12
4 M1 oe
(y =) 2
13
A1 oe
6 20x2 + 15xy 8xy 6y2 M1 oe
Must have 4 terms with at least 3 correct
20x2 + 15xy 8xy 6y2 A1
20x2 + 7xy 6y2 A1ft ft From M1 A0AQA Level 2 Certificate in Further Mathematics - 8360/1- Set 2 - Paper 1 - Practice Paper
5
Q Answer Mark Comments
7(a) 3(42) + 4 (3)2 (3) M1
46 A1
7(b) 3x2 + x – 52 – 5 (= 0) M1
3x2 + x – 30 (= 0) M1
(3x ± a)(x ± b) (= 0) M1 ab = 30 or a + b = 1
3
10
and 3 A1 oe
8(a) Gradient = –2 M1
y + 6 = – 2(x – 1) M1
y = – 2x – 4 A1
Alt 8(a) Gradient = –2 M1
6 = 2(1) + c or c = 4 M1
y = 2x 4 A1
8(b)
Gradient =
12
M1 ft Their gradient in (a)
y – 4 =
12
(x + 5) M1
Substituting y = 0 M1 Dep Dep on attempt at straight line equation
x = –13 or (–13, 0) A1
Alt 8(b)
Gradient =
12
M1 ft Their gradient in (a)
4 =
12
(5) + c or c = 6
12
M1
y =
12
x + 6
12
and substituting y = 0 M1 Dep Dep on attempt at straight line equation
x = 13 or (13, 0) A1
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