Sophia College Algebra Milestone 2

UNIT 2 — MILESTONE 2 Score 19/20 You passed this Milestone 19 questions were answered correctly. 1 question was answered incorrectly. 1 Consider the following subset of the real number line How can this set be exp ...

UNIT 2 — MILESTONE 2 Score 19/20 You passed this Milestone 19 questions were answered correctly. 1 question was answered incorrectly. 1 Consider the following subset of the real number line How can this set be expressed using inequalities? -3 ≤ x < 1 -3 ≥ x > 1 -3 < x ≤ 1 -3 > x ≥ 1 RATIONALE 5/25/2021 Sophia :: Welcome https://snhu.sophia.org/spcc/college-algebra-3/milestone_take_feedbacks/9199062 2/13 CONCEPT Introduction to Inequalities 2 What is the solution set for the following inequality? 2x + 8x ≥ 15 + 14x + 9 x ≤ -6 x ≤ -0.85 x ≥ -6 x ≥ -0.85 RATIONALE Before solving for x, make sure that each side of the inequality is fully simplified. On the right side, we will add 15 and 9. On the right side, 15 plus 9 is 24. On the left side, we can combine 2x and 8x. 2x plus 8x is 10x. Now we can begin to solve for x by applying inverse operations to both sides of the inequality. First, subtract 14x from both sides. Subtracting 14x from both sides cancels the 14x term on the right side of the inequality, leaving x terms on only the left side. Finally, divide both sides of the inequality by -4. Remember that the sign of the inequality sign changes whenever you multiply or divide by a negative number! The solution to the inequality is x ≤ -6. CONCEPT Solve Linear Inequalities 3 John is driving at a constant speed of 40 miles per hour. How long does it take him to travel 50 miles? An hour and 48 minutes An hour and 15 minutes 5/25/2021 Sophia :: Welcome https://snhu.sophia.org/spcc/college-algebra-3/milestone_take_feedbacks/9199062 3/13 An hour and 8 minutes An hour and 30 minutes RATIONALE To find how long it will take John to travel 50 miles, we can use the distance, rate, time formula and solve for time. Plug in 50 miles for the distance, and 40 miles per hour for the rate, or speed. Once we have plugged in the values, we need to write miles per hour as a fraction: 40 miles over 1 hour. When dividing by a fraction, we can change this into a multiplication problem and multiply by the reciprocal of 40 miles per 1 hour, which would be 1 hour over 40 miles. Rewrite 50 miles as a fraction over 1, and multiply this by the reciprocal of 40 mph. Next, multiply the numerators and denominators of the fractions. Multiplying across the numerator and denominator, produces 50 over 40. The units of miles cancel, so we are left with hours. Finally, divide 50 by 40. It will take John 1.25 hours. However, because we must express our answer in hours and minutes, we must convert 0.25 hours to minutes. Using the conversion factor, 60 minutes to 1 hour, evaluate the fractions by multiplying the numerators and denominators. Multiplying across the numerator and denominator produces 0.25 times 60, or 15. Units of hours cancel, leaving only minutes. It will take John 1 hour and 15 minutes to travel 50 miles at a constant speed of 40 miles per hour. CONCEPT Distance, Rate, and Time 4 The number of employees who will be able to perform a specific task is given by the equation , where N is the number of people who are able to perform the task, and t is time (in days). How long will it take until 100 employees are able to perform the task? 16 days 20 days 4 days 8 days RATIONALE The number of employees who can perform the task is modeled by this equation. To find how long it will take until 100 employees can perform the task, we will substitute this value for N and solve for t. Once N is replaced, we can solve for t. First, divide both sides by 25 to undo 25 multiplied by the square root of t. On the left, 100 divided by 25 is 4. To undo the square root of t on the right, square both sides. On the left, 4 squared is 16. It will take 16 days for 100 employees to be able to perform the task. CONCEPT Solving Multi-step Equations 5 5/25/2021 Sophia :: Welcome https://snhu.sophia.org/spcc/college-algebra-3/milestone_take_feedbacks/9199062 4/13 The value V (in dollars) of an airplane depends on the flight hours x as given by the formula V = 1,800,000 – 250x. After one year, the value of the plane is between $1,200,000 and $1,300,000. Which range for the flight hours does this correspond to? 2000 ≤ x ≤ 2400 2200 ≤ x ≤ 2500 1800 ≤ x ≤ 2100 1500 ≤ x ≤ 1800 RATIONALE The value of the airplane is modeled by this equation. To find the range for the flight hours, construct an inequality with the expression for the plane's value in between the lower and upper values for the plane given in the problem. Solving these kinds of inequalities is very similar to solving equations. Use inverse operations to isolate the variable, but be sure to perform the same operations in all parts of the inequality. First, subtract 1,800,000 from all three parts of the inequality. Subtracting 1,800,000 from all three parts cancels out the 1,800,000 in the middle, leaving only the x term. Next, divide all parts of the inequality by -250 Remember that whenever you multiple or divide an inequality by a negative number, the sign of the inequality symbols change direction. We are now left with only a x term in the middle. However, the inequality symbols are not arranged in standard form, with the smaller number first. This is an equivalent statement from the previous inequality. If you re-write the inequalities in this way, you'll notice the symbols change directions, too.