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Assignment -01 . Wayne State University CSE 5301( Questions with complete solution)

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Assignment -01 . Wayne State University CSE 5301( Questions with complete solution)NISARG PAWAR STUDENT ID: 1001720812 CSE5301 Homework-1 DATA: There are three rooms in a house: the kitchen, the b ... edroom and the living room. There is a radio transmitter outside the home that can be received in each room. A user is wearing a device that can measure the strength of the signal; however, due to noise in the sensor and in the environment, each time the device reads the signal strength, the result may contain an error. We know that the bedroom should have a reading of 50 units; the kitchen a reading of 51 units; and the living room a reading of 52 units in 50% of the cases and 53 in the other 50% of the cases. Someone has made a lot of measurements and created the following table representing the probability distribution for a given reading is in a particular room (P(Reading|Room)): Room\Readi ng <= 49 50 51 52 53 54<= Bedroom 0.33 0.41 0.13 0.08 0.05 0 Kitchen 0.07 0.13 0.53 0.14 0.08 0.05 Living Room 0.06 0.09 0.13 0.28 0.33 0.11 Solution: Here Let, Bedroom = B Kitchen = K Living Room = L and P(B) = P(K) = P(L) = ⅓ (Probability of picking a room at random) (A) Solution: Here we need to calculate P(B|52), P(L|52) and P(L|52). We have: P(52|B) = 0.08 P(52|K) = 0.14 [Show More]

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