Answer Key: Sweet Stoichiometry Reactions
Sample average masses included, but actual masses will vary, as will the calculations using molar mass.
Complete the following table using the candy provided. Do not unwrap or
...
Answer Key: Sweet Stoichiometry Reactions
Sample average masses included, but actual masses will vary, as will the calculations using molar mass.
Complete the following table using the candy provided. Do not unwrap or eat any candy.
Complete the missing information in the table.
Element/Compound Symbol Molar Mass (g/mol)
Butterscotch Bs 5.324
Peppermint Pe 5.002
Pepperscotch Bs2Pe 2(5.324) + 5.002 = 15.650
Animal Cracker An 1.867
Smarties St4 0.517
Animartie An3St2 3(1.867) + 2(0.517) = 6.635
Skittles Sk2 2(1.062) = 2.124
Starburst Su 4.991
Skittleburst Sk2Su2 2(1.062) + 2(4.991) = 12.106
M&M’s Mm5 5(0.870) = 4.350
Jelly beans Jb2 2(1.148) = 2.296
Mmelly MmJb3 0.870 + 3(1.148) = 4.314
Use the candy in the bag to illustrate each reaction and answer the questions.
1. Butterscotch reacts with peppermint to form pepperscotch.
a. Write the balanced equation.
2 Bs + Pe Bs2Pe
b. How many moles of pepperscotch can be formed by the elements in the bag?
1 mol Bs2Pe can be formed
c. How many moles of butterscotch were used?
2 mol Bs were used
d. How many moles of peppermint were used?
1 mol Pe was used
e. If 18 moles of pepperscotch were produced, how many moles of butterscotch
and how many moles of peppermint were used in the reaction?
18 mol Bs2Pe 2 mol Bs = 36 mol Bs 18 mol Bs2Pe 1 mol Pe = 18 mol Pe
1 mol Bs2Pe 1 mol Bs2Pe
f. How many moles of pepperscotch can be made with 48.0 g of peppermints?
48.0 g Pe 1 mol Pe 1 mol Bs2Pe = 9.60 mol Bs2Pe
5.002 g Pe 1 mol Pe
g. How many grams of pepperscotch can be produced if you start with 50.0 g of
butterscotch?
50.0 g Bs 1 mol Bs 1 mol Bs2Pe 15.650 g Bs2Pe = 73.5 g Bs2Pe
5.324 g Bs 2 mol Bs 1 mol Bs2Pe
2. Animal cracker reacts with smarties to form animartie.
a. Write the balanced equation.
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