Conduct a Hypothesis Test for Proportion - P-Value Approach.

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A researcher claims that the proportion of students who have traveled abroad is greater than 45%. To test this claim, a random sample of 750 students is taken and its determined that 374 students ha... ve traveled abroad. The following is the setup for this hypothesis test: H0:p=0.45 Ha:p>0.45 In this example, the p-value was determined to be 0.004. Come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) A: The decision is to reject the Null Hypothesis. The conclusion is that there is enough evidence to support the claim. A researcher claims that the proportion of students who have traveled abroad is greater than 45. To test this claim, a random sample of 750 students is taken and its determined that 374 students have traveled abroad. The following is the setup for this hypothesis test: H0:p=0.45 Ha:p>0.45 Find the p-value for this hypothesis test for a proportion and round your answer to 3 decimal places. The following table can be utilized which provides areas under the Standard Normal Curve: z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 2.4 0.992 0.992 0.992 0.992 0.993 0.993 0.993 0.993 0.993 0.994 2.5 0.994 0.994 0.994 0.994 0.994 0.995 0.995 0.995 0.995 0.995 2.6 0.995 0.995 0.996 0.996 0.996 0.996 0.996 0.996 0.996 0.996 2.7 0.997 0.997 0.997 0.997 0.997 0.997 0.997 0.997 0.997 0.997 2.8 0.997 0.998 0.998 0.998 0.998 0.998 0.998 0.998 0.998 0.998 2.9 0.998 0.998 0.998 0.998 0.998 0.998 0.998 0.999 0.999 0.999 A: P-Value: 0.004 A hospital administrator claims that the proportion of knee surgeries that are successful is 87%. To test this claim, a random sample of 450 patients who underwent knee surgery is taken and it is determined that 371 of these patients had a successful knee surgery operation. The following is the setup for this hypothesis test: H0:p = 0.87 Ha:p ≠ 0.87 Find the p-value for this hypothesis test for a proportion and round your answer to 3 decimal places. The following table can be utilized which provides areas under the Standard Normal Curve: z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -2.9 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.001 0.001 0.001 -2.8 0.003 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 0.002 -2.7 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 0.003 -2.6 0.005 0.005 0.004 0.004 0.004 0.004 0.004 0.004 0.004 0.004 -2.5 0.006 0.006 0.006 0.006 0.006 0.005 0.005 0.005 0.005 0.005 A: P-Value: 0.005 A college administrator claims that the proportion of students that are nursing majors is less than 40%. To test this claim, a group of 400 students are randomly selected and its determined that 149 are nursing majors. The following is the setup for this hypothesis test: H0:p=0.40 Ha:p<0.40 Find the p-value for this hypothesis test and round your answer to 3 decimal places. Use the following portion of the Standard Normal Table: (To read the Standard Normal table, match the ones and tenths digits of the z-value in the first column with the correct hundredths digit in the first row.) z... −1.3−1.2−1.1−1.00.00...0.0970.1150.1360.1590.01...0.09 50.1130.1340.1560.02...0.0930.1110.1310.1540.03...0.0920 .1090.1290.1520.04...0.0900.1080.1270.1490.05...0.0890.1 060.1250.1470.06...0.0870.1040.1230.1450.07...0.0850.102 0.1210.1420.08...0.0840.1000.1190.1400.09...0.0820.0990. 1170.138 A: P-Value: 0.131 A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test this claim, a random sample of 700 employees is taken and 305 employees are determined to earn more than $50,000. The following is the setup for this hypothesis test: H0:p=0.40 Ha:p<0.40 In this example, the p-value was determined to be 0.973. Come to a conclusion and interpret the results for this hypothesis test for a proportion (use a significance level of 5%) [Show More]

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