Chemistry > TEST BANK > CHEM 3413 Chapter 05 Phases and Solutions CHEM 3413 LAIDLER MEISER SANCTUARY PHYSICAL CHEMISTRY PROB (All)
CHEM 3413 Chapter 05 Phases and Solutions CHEM 3413 LAIDLER MEISER SANCTUARY PHYSICAL CHEMISTRY PROBLEMS ANSWERS SOLUTIONS Chapter 5 *problems with an asterisk are slightly more demanding Thermod... ynamics of Vapor Pressure 5.1. Diamonds have successfully been prepared by submitting graphite to high pressure. Calculate the approximate minimum pressure needed using ΔfG = 0 for graphite and ΔfG = 2.90 × 103 J mol–1 for diamond. The densities of the two forms may be taken as independent of pressure and are 2.25 and 3.51 g cm–3, respectively. Solution 5.2. The molar entropy of vaporization of water is 108.72 J K–1 at 760 Torr. The corresponding densities of liquid water and water vapor are 0.958 kg dm–3 and 5.98 × 10–4 kg dm–3, respectively. Calculate the change of pressure for a one-degree change in temperature. Solution 5.3. Calculate the heat of vaporization of water at 373.15 K and 101.325 kPa using the Clausius-Clapeyron equation. The vapor pressure of water is 3.17 kPa at 298.15 K. Compare your answer to the CRC Handbook1 value. Solution 5.4. Liquid water and vapor are in equilibrium at the triple point of water (0.00603 atm and 273.16 K). Assuming that the enthalpy of vaporization of water does not change over the temperature range considered, calculate the equilibrium vapor pressure of water at 373.15 K. Comment on the assumption made here. (ΔvapH° = 40 656 J mol–1 at 1 atm.) Solution 5.5. Estimate the vapor pressure of iodine under an external pressure of 101.3 × 106 Pa at 313.15 K. The density of iodine is 4.93 g cm–3. The vapor pressure at 101.3 kPa is 133 Pa. Solution5.6. The cubic expansion coefficient is given by α = 1/V (∂V/∂T)P. According to Ehrenfest’s or Tisza’s theory, find the order of the [Show More]
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