Mathematics > MILESTONE > BUS 100 - Introduction to Business Sophia Learning, College Algebra, Milestone 1 (All)

BUS 100 - Introduction to Business Sophia Learning, College Algebra, Milestone 1

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18 questions were answered correctly. 2 questions were answered incorrectly. 1 Find the solution for x if |6x + 8|=32. • • • correct • RATIONALE To solve this equation, we will need... to create two separate equations without absolute value bars. One equation will contain the expression exactly as it appears within the absolute value bars. The second equation must consider the case when the expression has the opposite value. Next, solve each equation separately, starting with 6x + 8=32. To solve for x, start by subtracting 8 from both sides. CONCEPT Absolute Value Equations 2 Suppose that 3y – 5 = 45 and y = 3x – 2. Which of the following equations is equivalent to 3y – 5 = 45, but written only in terms of x? • 9x – 6 = 50 correct • 9x – 6 = 40 • 15x – 10 = 40 On the left, we have only 6x. On the right 32 minus 8 is 24. Then divide both sides by 6 to isolate x. The solution for the first equation is x = 4. The same process can be applied to the second equation 6x + 8 = -32. To solve, start by subtracting 8 from both sides. On the left, we have only 6x. On the right -32 minus 8 is -40. Then divide both sides by 6 to isolate x. The solution for the second equation is . The two solutions to |6x + 8| = 32 are x = 4 and . • 15x – 10 = 50 RATIONALE CONCEPT Substitution in multi-step linear equations [Show More]

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