Mathematics > GCSE MARK SCHEME > Mark Scheme (Provisional) Summer 2021 Pearson Edexcel International GCSE In Mathematics B (4MB1) Pap (All)

Mark Scheme (Provisional) Summer 2021 Pearson Edexcel International GCSE In Mathematics B (4MB1) Paper 01

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Question Working Answer Mark Notes 1 2 2 (4 9 ) x y y − or 2 (4 9 ) y xy x − or xy y (8 18) − M1 Correct partial factorisation by taking out a common factor consisting of at least 2 differe... nt terms. Implied by correct answer. Do Not ISW 2 (4 9) xy y − 2 A1 Completely correct Total 2 marks 2(a) 1 B1 No other squares shaded (b) 1 B1 No other squares shaded Total 2 marks 3 y y tx − = 4 2 or y y 4 2 x t t = + M1 y y 4 2 x t − = 2 A1 oe eg y y 4 2 x t t = − or y y 4 2 x t − + = − Allow the other way round eg y y 4 2 x t − = Working not required, so correct answer scores full marks (unless from obvious incorrect working) Total 2 marks http://britishstudentroom.wordpress.com/Question Working Answer Mark Notes 4 (1 0.64 75 −  ) or 0.64 75  or 75 0.64 75 −  oe M1 27 2 A1 Working not required, so correct answer scores full marks (unless from obvious incorrect working) Total 2 marks 5 Method 1 Method 2 2 17 y = oe 4 16 x = − oe M1 Eliminating either x or y to get a correct equation in one unknown 4 4 "8.5" 18 x +  = or 4 16 x = − 4 (" 4") 6 18  − + = y or 2 17 y = M1 Subst their x or y value into either equation or start again. If M1 has already been awarded this can be implied by a correct value for x and y. NB The Speech marks around the –4 ("–4") means this follows through from their value x = – 4 y = 8.5 3 A1 dep on 1st M1 being awarded Total 3 marks 6 AD = − − =  25 50 35 20 2 ( )2   M1 Correct calculation to find AD or[ AD =] 20 Allow using their h = − (50 35) if marked on their diagram provided h is between 5 and 25. Must see the Pythagoras calculation eg 25 18 2 2 − NB Anything appearing in square brackets is not required [Perimeter =] 50 25 35 "20" + + + M1 dep on previous method mark being awarded. Follow through their "20". 130 3 A1 Working not required, so correct answer scores full marks (unless from obvious incorrect working) Total 3 marks http://britishstudentroom.wordpress.com/Question Working Answer Mark Notes 7 Sight of 3n or 3n – 8 or n + 20 M1 One correct expression seen. May be seen as part of an equation n n + = − 20 3 8oe A1 Correct equation 14 3 A1 dep on previous A mark awarded Total 3 marks 8 Arc, centred B, radius 4 cm, drawn within ABCD M1 Ignore any parts outside of ABCD. Arc drawn should lie between an arc radius 3.8 cm and arc radius 4.2 cm. It should intersect AB and BC and be complete within ABCD 2 pairs of intersecting arcs of equal radius centred at A and D with line drawn through intersection points oe M1 Ignore any parts outside of ABCD. Construction lines must be shown. Line should lie between 4.3 cm and 4.7cm from AB. R identified by shading and labelled 3 A1 dep on both previous method marks awarded. Allow just shading or just R if it is clear which the area is. Total 3 marks 9 27 1.08 or 27 100 108  [=25] M1 For a correct method to find the original price. M2 for 135 27 108  oe 27 " " 1.35 1.08  or 27 35 " 100" "25" 108 100  +  oe M1 dep on previous method mark being awarded. For a correct method to increase their original price by 35% 33.75 3 A1 oe Working not required, so correct answer scores full marks (unless from obvious incorrect working) Total 3 mark [Show More]

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