Physics > GCSE MARK SCHEME > Pearson Edexcel International GCSE In Physics (4PH1) Paper 1P and Science (Double Award) (4SD0) Pape (All)
Pearson Edexcel International GCSE In Physics (4PH1) Paper 1P and Science (Double Award) (4SD0) Paper 1P. Mark Scheme (Results) January 2021
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Question number Answer Notes Marks 1 kinetic; 6 main sequence; contract; expand; supernova; neutron star; Total for Question 1 = 6 marksQuestion number Answer Notes Marks 2 (a) (i) (average)... speed = distance (moved) / time (taken); allow standard symbols and rearrangements e.g. v = s / t 1 allow s for speed, d for distance (ii) substitution; 2 evaluation; e.g. (speed =) 6.5 / 0.25 (speed =) 26 (m/s) (iii) correct conversion of EITHER m to km OR s to h; allow ECF from (ii) 2 full conversion from m/s to km/h AND consistent conclusion;; allow ECF from (ii) allow conversion of km/h to m/s e.g. 80km/h = 22.2m/s e.g. 26 (m/s) = 0.026 (km/s) OR 26 (m/s) = 93600 (m/h) 94 (km/h) => too fast allow 93.6 (km/h) (b) (i) acceleration is the gradient (of the graph); 2 graph has a constant gradient; allow line on graph is straight (ii) acceleration = change in velocity / time; allow standard symbols and rearrangements e.g. a = (v-u) / t, a = ∆v / t 1 (iii) correct reading of either two velocity values or time interval taken from graph; allow attempt at gradient calculation 3 correct substitution into formula; evaluation; e.g. u = 5 (m/s), v = 24 (m/s) OR t = 60 (s) allow (v – u =) 19 seen (a =) 24-5 / 60 (a =) 0.32 (m/s2) allow range of 0.30-0.32 Total for Question 2 = 11 marksQuestion number Answer Notes Marks 3 (a) idea that if one bulb fails all bulbs turn off; allow idea that bulbs cannot be controlled individually 1 (b) any one from: 1 • less likely to overheat; • idea that the circuit is simpler; accept uses fewer wires • lower voltage bulbs; • all bulbs controlled with one switch; (c) (i) voltage = current × resistance; allow standard symbols and rearrangements e.g. I = V / R 1 (ii) substitution; 3 rearrangement; evaluation; e.g. 33 = I × 390 (I =) 33 / 390 (I =) 0.085 (A) allow 0.08, 0.0846… condone 0.084 (iii) dimensionally correct substitution into E = V × I × t; allow ECF from (ii) 4 conversion of hours to seconds; allow 60 × 60 or 9000 seen anywhere in working use of 7 bulbs; evaluation; 23760-25245 = 3 marks (x7 not used) e.g. 6.60-7.01 = 2 marks E = 33 × 0.085 × 2.5 2.5 hours = 9000 seconds voltage used = 231 OR ×7 used in working (E =) 180 000 (J) allow answer between 165000 to 180000 (d) brightness is greater in lamp Y; allow RA 3 with any two from: more energy transferred to each bulb in lamp Y; bulbs in lamp Y have a larger voltage / 46 V; resistance of (circuit in) lamp Y is less; current in bulb / circuit in lamp Y is greater; Total for Question 3 = 13 marks [Show More]
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