Mathematics > GCSE MARK SCHEME > Mark Scheme (Results) January 2022 Pearson Edexcel International GCSE Mathematics A (4MA1) Paper 1HR (All)

Mark Scheme (Results) January 2022 Pearson Edexcel International GCSE Mathematics A (4MA1) Paper 1HR

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International GCSE Maths Apart from Questions 10, 14, 15, 22, 24 the correct answer, unless clearly obtained by an incorrect method, should be taken to imply a correct method. Q Working Answer Mark... Notes 1 (a) −2, −1, 0, 1, 2 2 B2 for −2, −1, 0, 1, 2 with no additions or repeats (B1 for 4 of −2, −1, 0, 1, 2 with no additions or repeats or for 6 values with no more than one incorrect value e.g. all of −2, −1, 0, 1, 2, 3 or for 5 values with one error) (b) Closed circle at x = 1 and a line with an arrow to the left 1 B1 for a closed circle at x = 1 and a line with an arrow of any length to the left Allow ] for a closed circle Allow a line without an arrow if it reaches to at least −3 Total 3 marks 2 0.65 × 300 oe M1 195 A1 (SCB1 for 105) Total 2 marks https://britishstudentroom-b430a.web.app/3 12.8 16 2 2 2 x oe or 163.84 256 x2 or ( )16 12.8 ( 92.16) x2 2 2 or ( ) 256 163.84 ( 92.16) x2 4 M1 for applying Pythagoras theorem correctly Allow cos 36.9... 1 12.8 ( ) 16 −     =   and 16 sin(36.9...) (sin 90) x = ( ) 16 12.8 ( 92.16) x 2 2 (= 9.6) or ( ) 256 163.84 ( 92.16) x (= 9.6) M1 for square rooting Allow 16 sin(36.9...) (sin 90) x =  (12.8 – “9.6”) + “9.6” + “9.6” + 16 + 16 + 16 oe M1 (dep on M1) for a complete method to find the perimeter 70.4 A1 oe e.g. 352 5 Total 4 marks 4 (a) 15, 0, −1, 3 2 B2 for 4 correct values (B1 for 2 or 3 correct values) (b) (−2, 15) (−1, 8) (0, 3) (2, −1) (3, 0) (4, 3) 2 M1 (dep on B1) ft from (a) for at least 5 points plotted correctly correct graph A1 for a correct graph (clear intention to go through all the points and which must be curved at the bottom) Note: If a fully correct graph is shown, but an incomplete table is shown in (a), then award the marks for (a) Total 4 marks https://britishstudentroom-b430a.web.app/5 4 B1 for 80 for 75 74 2 a + = oe or 73 M1 for setting up an equation using the median or for 73 for 80 – 16 (= 64) oe M1 for using the range correctly or for 64 64, 73, 80 A1 answers can be in any order Total 4 marks 6 (a) 36, 72, 108, ... and 120, 240, 360, ... or 2, 2, 3, 3 and 2, 2, 2, 3, 5 or or 36 120 12  or 2, 2, 2, 3, 3, 5 oe 2 36 120 2 18 60 3 9 30 3 10 2 M1for any correct valid method e.g. for starting to list at least three multiples of each number 2, 2, 3, 3 and 2, 2, 2, 3, 5 seen (may be in a factor tree or a ladder diagram and ignore 1) (Allow 2 × 2 as 4) or a fully correct “Venn” diagram 360 A1 or 23 × 32 × 5 oe (allow 23 . 32 . 5) (b) 5 7 11 2 4   2 B2 for 5 7 11 2 4   (in any order) (B1 for 660 275 or correct unsimplified product or 5 7 11 a b c   where 2 of a, b and c are correct) Total 4 marks 2 2 3 3 2 5 https://britishstudentroom-b430a.web.app/7 220 ÷ 80 (= 2.75 or 11 4 ) oe M1 for a method to find the time from B to C 50 72 60  (= 60) oe M1 for a method to find the distance from C to D Allow 0.83(333…) to 2 dp truncated or rounded 245 220 "60" 525 50 73 2.5 "2.75" 12 60   + +   =   + +   oe M1 for a complete method to find the average speed for entire journey 0.83(333…) to 2 dp truncated or rounded 6.0(8333…) to 2 sf truncated or rounded 86.3 A1 for 86.3 – 86.4 Total 4 marks 8 (a) 50 000 1 B1 (b) 6 10  −5 1 B1 (c) 2.5 10  512 700 − or 2.5 10  n or 0.25 10  −187 or p10−188 where 1 ≤ p < 10 2 M1 2.5 10  −188 A1 Total 4 marks 9 (a) x9 1 B1 cao (b) 64y6 2 B2 for 64y6 (B1 for ky6 where k ≠ 64 or 64ym where m ≠ 6) (c) (n ± 3)(n ± 4) 2 M1 for (n ± 3)(n ± [Show More]

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