Chemistry > Lab Experiment > Kinetics Post Lab - University of California, Los Angeles CHEM 14BL (All)

Kinetics Post Lab - University of California, Los Angeles CHEM 14BL

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Chem XL 14BL 11/13/20 The Reaction of Red Food Color with Bleach Data and Data Analysis i. Group members/responsibilities: - Laura Sarah R’bibo: Data collection and analysis - Isabel Bellanti-... Diehl: Tables and graphs - Marina Hierl: Analysis and conclusion ii. Calculate the molarity for the stock bleach (NaOCl/hypochlorite). 0.0600 ?? ?? × 1.10 ?? ???? × 1000 ???? ?? = 66.00 ?? ?? 66.00 ?? ?? × 1 ?????? 74.44 ?? = 0.8866 ?????? ?? = 0.8866 ?? iii. Calculate the precise molarity of food-dye solutions 1-3. Molecular weight of food dye = 879.9 g/mol Mass of food dye = 0.233g Solution 1: 0.233?? × 1 ?????? 879.9 ?? = 0.0002648 ?????? = 2.65 × 10−4?????? 2.65 × 10−4?????? 0.10 ?? = 0.00265 ?? = 2.65 × 10−3?? Solution 2: ??2 = ??1??1 ??2 ??2 = 2.65 × 103?? × 10 ???? 100 ???? = 2.65 × 10−4?? Solution 3: ??3 = 2.65 × 10−3?? × 5 ???? 100 ???? = 1.325 × 10−5?? iv. Calculate the initial concentration of the food-dye solution in each trial 1-3. Trial 1: ??1 = 1.325 × 10−5??; ??1 = 3.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 1.325 × 10−5?? × 3.0???? 6.0???? = 6.625 × 10−6?? Trial 2: ??1 = 1.325 × 10−5??; ??1 = 3.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 1.325 × 10−5?? × 3.0???? 6.0???? = 6.625 × 10−6?? Trial 3: ??1 = 1.325 × 10−5??; ??1 = 5.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 1.325 × 10−5?? × 5.0???? 6.0???? = 1.104 × 10−5?? v. Calculate the initial concentration of the bleach solution for each trial 1-3. Trial 1: ??1 = 0.887??; ??1 = 1.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 0.887?? × 1.0???? 6.0???? = 0.148?? Trial 2: ??1 = 0.887??; ??1 = 2.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 0.887?? × 2.0???? 6.0???? = 0.296?? Trial 3: ??1 = 0.887??; ??1 = 1.0???? ; ??2 = 6.0???? ??2 = ??1??1 ??2 = 0.887?? × 1.0???? 6.0???? = 0.148?? vi. Using Beer’s Law, calculate the molar absorptivity constant for the food-dye. ?? = ∈ ???? ?? = 1.16 ?? = 1.22???? ?? = 1.325 × 10−5 ?????? ?? ∈ = ?? ???? = 1.16 1.22???? × 1.325 × 1 [Show More]

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