Version: 1.1 Final Mark Scheme
*226A7357/1/MS*
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant
questions,
...
Version: 1.1 Final Mark Scheme
*226A7357/1/MS*
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
2
Mark schemes are prepared by the Lead Assessment Writer and considered, together with the relevant
questions, by a panel of subject teachers. This mark scheme includes any amendments made at the
standardisation events which all associates participate in and is the scheme which was used by them in
this examination. The standardisation process ensures that the mark scheme covers the students’
responses to questions and that every associate understands and applies it in the same correct way.
As preparation for standardisation each associate analyses a number of students’ scripts. Alternative
answers not already covered by the mark scheme are discussed and legislated for. If, after the
standardisation process, associates encounter unusual answers which have not been raised they are
required to refer these to the Lead Examiner.
It must be stressed that a mark scheme is a working document, in many cases further developed and
expanded on the basis of students’ reactions to a particular paper. Assumptions about future mark
schemes on the basis of one year’s document should be avoided; whilst the guiding principles of
assessment remain constant, details will change, depending on the content of a particular examination
paper.
Further copies of this mark scheme are available from aqa.org.uk
Copyright information
AQA retains the copyright on all its publications. However, registered schools/colleges for AQA are permitted to copy material from this booklet for their own
internal use, with the following important exception: AQA cannot give permission to schools/colleges to photocopy any material that is acknowledged to a third
party even for internal use within the centre.
Copyright © 2022 AQA and its licensors. All rights reserved.
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Mark scheme instructions to examiners
General
The mark scheme for each question shows:
• the marks available for each part of the question
• the total marks available for the question
• marking instructions that indicate when marks should be awarded or withheld including the principle
on which each mark is awarded. Information is included to help the examiner make his or her
judgement and to delineate what is creditworthy from that not worthy of credit
• a typical solution. This response is one we expect to see frequently. However credit must be given on
the basis of the marking instructions.
If a student uses a method which is not explicitly covered by the marking instructions the same
principles of marking should be applied. Credit should be given to any valid methods. Examiners should
seek advice from their senior examiner if in any doubt.
Key to mark types
M mark is for method
R mark is for reasoning
A mark is dependent on M marks and is for accuracy
B mark is independent of M marks and is for method and accuracy
E mark is for explanation
F follow through from previous incorrect result
Key to mark scheme abbreviations
CAO correct answer only
CSO correct solution only
ft follow through from previous incorrect result
‘their’ Indicates that credit can be given from previous incorrect result
AWFW anything which falls within
AWRT anything which rounds to
ACF any correct form
AG answer given
SC special case
OE or equivalent
NMS no method shown
PI possibly implied
sf significant figure(s)
dp decimal place(s)
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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AS/A-level Maths/Further Maths assessment objectives
AO Description
AO1
AO1.1a Select routine procedures
AO1.1b Correctly carry out routine procedures
AO1.2 Accurately recall facts, terminology and definitions
AO2
AO2.1 Construct rigorous mathematical arguments (including proofs)
AO2.2a Make deductions
AO2.2b Make inferences
AO2.3 Assess the validity of mathematical arguments
AO2.4 Explain their reasoning
AO2.5 Use mathematical language and notation correctly
AO3
AO3.1a Translate problems in mathematical contexts into mathematical processes
AO3.1b Translate problems in non-mathematical contexts into mathematical processes
AO3.2a Interpret solutions to problems in their original context
AO3.2b Where appropriate, evaluate the accuracy and limitations of solutions to problems
AO3.3 Translate situations in context into mathematical models
AO3.4 Use mathematical models
AO3.5a Evaluate the outcomes of modelling in context
AO3.5b Recognise the limitations of models
AO3.5c Where appropriate, explain how to refine models
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Examiners should consistently apply the following general marking principles
No Method Shown
Where the question specifically requires a particular method to be used, we must usually see
evidence of use of this method for any marks to be awarded.
Where the answer can be reasonably obtained without showing working and it is very unlikely that the
correct answer can be obtained by using an incorrect method, we must award full marks. However,
the obvious penalty to students showing no working is that incorrect answers, however close, earn no
marks.
Where a question asks the student to state or write down a result, no method need be shown for full
marks.
Where the permitted calculator has functions which reasonably allow the solution of the question
directly, the correct answer without working earns full marks, unless it is given to less than the
degree of accuracy accepted in the mark scheme, when it gains no marks.
Otherwise we require evidence of a correct method for any marks to be awarded.
Diagrams
Diagrams that have working on them should be treated like normal responses . If a diagram has been
written on but the correct response is within the answer space, the work within the answer space
should be marked. Working on diagrams that contradicts work within the answer space is not to be
considered as choice but as working, and is not, therefore, penalised.
Work erased or crossed out
Erased or crossed out work that is still legible and has not been replaced should be marked. Erased
or crossed out work that has been replaced can be ignored.
Choice
When a choice of answers and/or methods is given and the student has not clearly indicated which
answer they want to be marked, mark positively, awarding marks for all of the student's best attempts.
Withhold marks for final accuracy and conclusions if there are conflicting complete answers or when an
incorrect solution (or part thereof) is referred to in the final answer.
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
1 Circles the correct answer 1.2 B1 x y + = 2 2 1
Question 1 Total 1
Q Marking instructions AO Marks Typical solution
2 Circles the correct answer 1.1b B1 2
Question 2 Total 1
Q Marking instructions AO Marks Typical solution
3 Circles the correct answer 2.2a R1 y x = 2log4
Question 3 Total 1
Q Marking instructions AO Marks Typical solution
4 Ticks the correct box 2.2a R1
Question 4 Total 1
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
5 Differentiates to obtain a correct
derivative either
( ) x − 3 4 2 OE
or
xxx − +− 3 2 4 24 48 32
PI by −32 obtained with no
errors seen in evaluating d
d
y
x
1.1b B1
d ( ) d
y x
x
= − 3 4 2
When x = 0
d
d
y
x
= −32
y =16
y x =− + 32 16
Substitutes x = 0 into their d
d
y
x
to
obtain a numerical value
or
PI by constant from their d
d
y
x
or
PI by −32 obtained with no
errors seen in evaluating d
d
y
x
1.1a M1
Obtains y x =− + 32 16
ACF
Award the mark at the first
opportunity and ISW any
incorrect rearrangement
No errors seen
1.1b A1
Question 5 Total 3
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
6(a) Expands to obtain the first two
terms
Can be unsimplified
Condone sign error
1.1a M1
x x
x
− ≈+ −
≈ −
1
2 1 1 1
2 22
1 1
4 Obtains − x
1 1
4 OE
Accept if listed as two separate
terms. Ignore any extra terms
1.1b A1
Subtotal 2
Q Marking instructions AO Marks Typical solution
6(b) States or uses at least one small
angle approximation correctly
either
sinkx kx ≈ or
x
x ≈ −
2
cos 1
2
3.1a M1
( ) x
x xx
x
x
x x
+ ≈ +−
≈ +−
≈+ −
2
2
2
sin 4 cos 4 1
2
4 1
4
1 1 4
4
Uses both small angle
approximations correctly for sine
and cosine
sinkx kx ≈ and x
x ≈ −
2
cos 1
2
Must have eliminated all trig
expressions
Inconsistent variables for angles
must eventually be consistent to
be awarded A1
1.1b A1
Uses their expansion from (a)
Must have replaced x with x2
or
Applies binomial theorem
correctly to x −
1
2 2
1
2
ignore any
extra terms
3.1a M1
Completes argument to obtain
x x
+ −
2
4 1
4
or + −x x
1 2 1 4
4
Accept any order of terms
Ignore higher powers of x
Must be in terms of x
Do not ISW
2.1 R1
Subtotal 4
Question 6 Total 6
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
7 Sketches one of the sections of
the curve shown below
Either
or
Condone translations
Do not allow the end points of
the curve turning to intersect the
asymptote
1.2 B1
Sketches the three branches
within the interval from 0 to 2π
Condone overlapping branches
Asymptotes need not be drawn
1.1a M1
Completes fully correct sketch
with asymptotes drawn at
approximately the correct
positions
Labelling not required and can
be ignored
Ignore anything after 2π or to
the left of O
1.1b A1
Question 7 Total 3
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
8(a)(i) Obtains correct y-intercept at P
(0,5) or y = 5 seen anywhere
PI by correct equation for line
PQ
3.1a B1
At P
?? = 0 ⇒ ?? = 5
Line PQ
3?? − 5?? = −25
5?? + 3?? = 83
(10, 11)
Obtains equation of PQ with
correct gradient. For example
y xc = +
3
5
or 5y – 3x = k
or
Forms an equation for the
distance or distance squared
from (0,5) to a point on L2
For example,
d2 = x2 + �− 5
3
?? + 68
3 �
2
3.1a M1
Obtains correct equation
ACF
1.1b A1
Solves simultaneous equations
for their PQ and L2 to obtain
values for x and y
Their PQ must not be a
horizontal or vertical line
Condone errors in
rearrangement of the
equation(s)
or
Minimises their distance or
distance squared equation to
find one coordinate
3.1a M1
Obtains (10, 11)
or
x y = = 10, 11
1.1b A1
Subtotal 5
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
8(a)(ii) Uses the distance formula to
find the value of PQ or 2 PQ
or
Uses Pythagoras theorem with
+2 2 10 6 seen
If the coordinates of P and Q are
incorrect, differences in x and y
must be clearly shown for M1
1.1a M1
= −+− ( ) ( )
= =
2 2 2 10 0 11 5
136 2 34
PQ
Completes demonstration to PQ
show that k = 2
Must have shown clear use of
distance formula
Condone not seeing x = 0
substituted in the distance
formula
Answer of 2 34 and no working
shown scores M1 R0
2.1 R1
Subtotal 2
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
8(b)(i) Uses a valid method to find a.
Evidence could be:
Forming the equation of the line
mid-way between L1 and L2
5 3 49 x y + = seen
or
Using (a , -17) as the mid-point
of a line segment from L1 to L2
For example:
() .
() .
( . .)
x x
x x
a
+− = =
+− = =
+ = =
5 3 17 15 13 2
5 3 17 83 26 8
26 8 13 2 20
2
or
Finding the mid-point of PQ
their (5 , 8) and using the
gradient of L1 and L2 = − 5
3
For example:
( )
a ( )
+ − =−
=+ =
8 5 5 17
5 5 3 20
or
Substitutes y = 17 and x = a into
y x = +
3 5
5
3.1a M1
( )
x y
a
a
+ =
+− =
=
5 3 49
5 3 17 49
20
Deduces a = 20 2.2a R1
Subtotal 2
Q Marking instructions AO Marks Typical solution
8(b)(ii) Forms expression of the form
( ) ( ) xa y ± +± 2 2 17
using a or their value of a
1.1a M1
( ) ( ) x y − ++ =
2 2 Obtains correct equation for 20 17 34
their value of a and their
radius2
=
k 2 17
2 from part (a)(ii)
for an integer value of k
Condone ( )2
34
1.1b A1F
Subtotal 2
Question 8 Total 11
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solution
9(a) Forms an appropriate equation
in x only by either
using the differences of at least
one pair of terms
or
Using the mean of the first and
third term = the second term
Condone missing brackets
or
Forms two simultaneous
equations in x and d
or
Substitutes x = 5 and
demonstrates that the three
terms obtained, 15, 26 and 37
have a common difference of 11
or
Shows that the sum formula for
an arithmetic series works when
x = 5
The approaches that substitute
x = 5 score a maximum of
M1 A0 R0
3.1a M1
xx x x ( ) ( )
x x
x
+− + = + − +
−=+
=
5 12 5 6 75 1
34 6
5
Therefore x = 5 is the only solution
Obtains a correct equation
or
Obtains two correct
simultaneous equations in x and
d
Need not be simplified
1.1b A1
Solves to conclude that x = 5
is the only solution
Must include the word ‘only’ OE
2.1 R1
Subtotal 3
Q Marking instructions AO Marks Typical solution
9(b)(i) Obtains 15 1.1b B1 a =15
Subtotal 1
Q Marking instructions AO Marks Typical solution
9(b)(ii) Obtains 11 1.1b B1 d = 11
Subtotal 1
MARK SCHEME – A-LEVEL MATHEMATICS – 7357/1 – JUNE 2022
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Q Marking instructions AO Marks Typical solut
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