Mathematics > QUESTIONS & ANSWERS > OCR Oxford Cambridge and RSA For use in June 2022 and November 2022 only GCSE (9—1) Mathematics J5 (All)

OCR Oxford Cambridge and RSA For use in June 2022 and November 2022 only GCSE (9—1) Mathematics J560/04, J560/05, J560/06 Higher Tier Formulae Sheet

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INSTRUCTIONS • Do not send this Formulae Sheet for marking. Keep it in the centre or recycle it. INFORMATION • This Formulae Sheet does not include advance information about the content of the ... June 2022 or November 2022 examinations. • This document has 2 pages. 2 © OCR 2022 J560 04/05/06 Oxford Cambridge and RSA Copyright Information OCR is committed to seeking permission to reproduce all third-party content that it uses in its assessment materials. OCR has attempted to identify and contact all copyright holders whose work is used in this paper. To avoid the issue of disclosure of answer-related information to candidates, all copyright acknowledgements are reproduced in the OCR Copyright Acknowledgements Booklet. This is produced for each series of examinations and is freely available to download from our public website (www.ocr.org.uk) after the live examination series. If OCR has unwittingly failed to correctly acknowledge or clear any third-party content in this assessment material, OCR will be happy to correct its mistake at the earliest possible opportunity. For queries or further information please contact The OCR Copyright Team, The Triangle Building, Shaftesbury Road, Cambridge CB2 8EA. OCR is part of the Cambridge Assessment Group; Cambridge Assessment is the brand name of University of Cambridge Local Examinations Syndicate (UCLES), which is itself a department of the University of Cambridge. Higher Tier Formulae Sheet Perimeter, Area and Volume Where a and b are the lengths of the parallel sides and h is their perpendicular separation: Area of a trapezium ( ) a b h 2 1 = + Volume of a prism = area of cross section # length Where r is the radius and d is the diameter: Circumference of a circle = 2πr = πd Area of a circle = πr 2 The Quadratic Formula The solutions of ax bx c 0 2 + + = where a ! 0 x a b b ac 2 4 2 ! = - - Pythagoras’ Theorem and Trigonometry c b a A c b a A C B In any right-angled triangle where a, b and c are the length of the sides and c is the hypotenuse: a b c 2 2 2 + = In any right-angled triangle ABC where a, b and c are the length of the sides and c is the hypotenuse: sinA c a = cosA c b = tanA b a = In any triangle ABC where a, b and c are the length of the sides: sine rule: sin s A in sin a B b C c = = cosine rule: a b c [Show More]

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