Materials
For this paper you must have:
• a ruler
• a scientific calculator
• the Physics Equations Sheet (enclosed).
Instructions
• Use black ink or black ball-point pen.
• Pencil should only be used for drawing.
...
Materials
For this paper you must have:
• a ruler
• a scientific calculator
• the Physics Equations Sheet (enclosed).
Instructions
• Use black ink or black ball-point pen.
• Pencil should only be used for drawing.
• Fill in the boxes at the top of this page.
• Answer all questions in the spaces provided.
• If you need extra space for your answer(s), use the lined pages at the end of
this book. Write the question number against your answer(s).
• Do all rough work in this book. Cross through any work you do not want to be
marked.
• In all calculations, show clearly how you work out your answer.
Information
• The maximum mark for this paper is 70.
• The marks for questions are shown in brackets.
• You are expected to use a calculator where appropriate.
• You are reminded of the need for good English and clear presentation in your answers.
Please write clearly in block capitals.
Centre number Candidate number
Surname
Forename(s)
Candidate signature
I declare this is my own work.
GCSE
COMBINED SCIENCE: TRILOGY
Foundation Tier
Physics Paper 1F
F
2
*02*
IB/M/Jun22/8464/P/1F
0 1 A student investigated how the potential difference across a filament lamp affects the
current in the lamp.
Figure 1 shows the circuit the student used.
Figure 1
0 1 . 1 Figure 2 shows a circuit symbol.
Figure 2
What component does the symbol represent?
[1 mark]
Tick () one box.
Ammeter
Battery
Lamp
Variable resistor
Do not write
outside the
box
3
*03*
Turn over ►
IB/M/Jun22/8464/P/1F
Do not write
outside the
0 1 box . 2 Which component from Figure 1 did the student use to adjust the potential difference
across the lamp?
[1 mark]
0 1 . 3 When the voltmeter was not connected to the circuit it gave a reading of 0.4 volts.
How can the student correct all the readings taken from the voltmeter?
[1 mark]
Tick () one box.
Add 0.4 volts to each reading
Divide each reading by 0.4 volts
Multiply each reading by 0.4 volts
Subtract 0.4 volts from each reading
Question 1 continues on the next page
4
*04*
IB/M/Jun22/8464/P/1F
Do not write
outside the
box 0 1 . 4 The student recorded three values of current for each potential difference.
Table 1 shows the results for 2.5 volts.
Table 1
Potential difference
in volts
Current in amps
1 2 3
2.5 0.54 0.58 0.53
Calculate the mean current in the lamp.
[2 marks]
Mean current = A
0 1 . 5 Calculate the power of the lamp when the potential difference across the lamp
was 4.8 V
The current in the lamp was 0.75 A
Use the equation:
power = potential difference × current
[2 marks]
Power = W
5
*05*
Turn over ►
IB/M/Jun22/8464/P/1F
Do not write
outside the
0 1 box . 6 Calculate the resistance of the lamp when the potential difference across the lamp
was 4.8 V
The current in the lamp was 0.75 A
Use the equation:
resistance = potential difference
current
[2 marks]
Resistance = Ω
0 1 . 7 Complete the sentence.
Choose answers from the box.
Each answer may be used once, more than once or not at all.
[2 marks]
decrease increase stay the same
Increasing the current in a filament lamp makes the temperature
of the lamp and the
resistance of the lamp .
Question 1 continues on the next page
6
*06*
IB/M/Jun22/8464/P/1F
Do not write
outside the
box
12
0 1 . 8 Which graph shows the relationship between potential difference and current for a
filament lamp?
[1 mark]
Tick () one box.
7
*07*
Turn over ►
IB/M/Jun22/8464/P/1F
Do not write
outside the
Turn over for the next question box
DO NOT WRITE ON THIS PAGE
ANSWER IN THE SPACES PROVIDED
8
*08*
IB/M/Jun22/8464/P/1F
Do not write
outside the
0 2 Figure 3 shows a lift near the bottom of a building. box
The lift is attached by a cable to a counterweight.
An electric motor moves the lift.
The lift is moving up.
Figure 3
0 2 . 1 As the lift moves up, how far does the counterweight move down?
[1 mark]
Tick () one box.
A shorter distance than the lift.
The same distance as the lift.
A longer distance than the lift.
9
*09*
Turn over ►
IB/M/Jun22/8464/P/1F
Do not write
outside the
0 2 box . 2 What happens to the gravitational potential energy of the counterweight as it
moves down?
[1 mark]
Tick () one box.
It decreases
It stays the same
It increases
0 2 . 3 Calculate the change in gravitational potential energy of the lift when it
moves up 4.0 m
The mass of the lift is 1300 kg
gravitational field strength = 9.8 N/kg
Use the equation:
gravitational potential energy = mass
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