FIRST ORDER SYSTEMS: DETERMINING EQUIVALENT SYSTEMS
ABSTRACT
Patent 7,493,601 makes the claim that an electrical, a
fluid system, and a thermal system are all equivalent systems.
Comparable laboratory experiments wer
...
FIRST ORDER SYSTEMS: DETERMINING EQUIVALENT SYSTEMS
ABSTRACT
Patent 7,493,601 makes the claim that an electrical, a
fluid system, and a thermal system are all equivalent systems.
Comparable laboratory experiments were design and used in
order to check for the validity of this claim. In this laboratory,
each of the three systems was analyzed in order to determine
whether or not the systems were equivalent. The 63.2% Method
was used to isolate the identifying characteristics of each
system. The systems were found to be both first order systems
but because of the large difference in magnitudes of their time
constants, τ, it was concluded that the electrical system was not
equivalent to the thermal and fluid systems.
INTRODUCTION
Grunch and Tromby, Attorneys at Law needed to test
the claims of Patent 7,493,601, that an electrical system, a fluid
system, and a thermal system are equivalent (ie. each system
has a comparable determining characteristic). Knowing if two
systems are equivalent is helpful in modern times because of
two reasons: (1) it allows a comparison between different
preferred types of systems, and (2) it allows experiments on one
system to give equivalent information about another (larger,
more expensive) systems.
In order to determine weather or not two systems’
responses are equivalent, they must be (1) of the same order
and (2) possess a system characteristic (e.g. τ for first order
systems) of the same magnitude.
Most systems fall into the category of either a zeroorder, first-order, or second-order system. These system’s
respective forms of differential equations can accurately
describe these systems. For example, first-order differential
equations are a very accurate way of portraying a first-order
system.
Each of these types of systems also has defining
features such as a time constant τ for first-order systems and ω
for second-order systems. These characteristics are defined as
the coefficients of the differential terms after the differential
equation has been put into standard form. These coefficients are
defining features and are the main contributors to how a system
responds. Because these coefficients are functions of time, they
act as indicators as to the rate at which the system responds to
the imposed change. For example, small values of τ in firstorder systems indicate a rapid time response, and a larger value
indicates a slower time response because of its inverse
relationship with time.
This experiment will test that claim made using the
basic knowledge of equivalent systems and mathematical
analysis previously described.
ANALYTICAL DEVELOPMENT
Upon observation, the first electrical system was
determined to be a simple RC circuit. Knowing RC circuits are
first-order systems, the electrical system was determined to be a
first-order system depending on the characteristic τ. As Patent
7,493,601 is defined, the electrical system consists of a series
circuit of a 2200 Ω resistor and a 100 µF capacitor. Using the
equation,
? = ? ∗ ? (1)
τ was predicted to be to be 0.22 seconds theoretically. For these
theoretical calculations, it was assumed that there were no
loading errors and that the frequency was less than the critical
frequency of the system.
Having recently studied a similar fluid system in class,
the fluid system was assumed to portray first order system
characteristics as well. From the preliminary analysis done in
lab,
? =
!"
!
(2)
where R is the resistance to outflow (226,466 1/(ft-s)), A is the
area of the basin (0.034088 ft2), and g is gravity (32.2 ft/s2).
This results in a theoretical τ of 240 seconds.
The thermal system was likewise assumed to be a first
order system, as the temperature of the inside of the box will
approach a limit similarly to a first-order differential equation.
Calculating the τ value for the second system was more
complicated however but can be done using equation (2) below:
? = ?? = ??!?!"#$%& (3)
where C
p is the specific heat of the fluid (water: 4.184 kJ/kg-K)
, m is the mass of the water (15 grams), and R is the total
thermal resistance of the system. In order to find R, equation
(3) was used [1]:
?
!"#$%& = ?! + !!!!!!!!! (4)
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