gilvin (jg47854) - 16. Magnetic fields 1 - meyers - (21235) 1 This print-out should have 16 questions. Multiple-choice questions may continue on 1. toward the left the next column or page - find al... l choices before answering. 2. into the page. 001 10.0 points 3. out of the page. A proton traveling to the right along the xaxis enters a region where there is a mag- 4. toward the top of the page. netic field of magnitude 1.1 T directed upward along the y-axis. 5. toward the right The charge on a proton is 1.60×10−19 If the proton experiences a force of 2.7 × 10−12 N, find its speed. Correct answer: 1.53409 × 107 m/s. Explanation: Let : B = 1.1 T , Fm = 2.7 × 10−12 N , and qe = 1.60 × 10−19 C . The magnetic force is Fm = q v B v = Fm q B 2.7 × 10−12 N 6. toward the bottom of the page. correct Explanation: The force on the electron is F = q v × B = −e v × B . The direction of the force is thus F = −v × B , pointing toward the bottom of the page , using right hand rule for v × B , and reversing the direction due to the negative charge on the electron. 003 10.0 points The magnetic field at the equator points = (1.6 × 10−19 C) (1.1 T) north. If you throw a positively charged object = 1.53409 × 107 m/s 002 10.0 points An electron is in a uniform magnetic field B that is directed out of the plane of the page, as shown. B B e− (for example, a baseball with some electrons removed) to the east, what is the direction of the magnetic force on the object? 1. Toward the west 2. Upward correct 3. Toward the east 4. Downward v Explanation: Use the right-hand rule: point your index B B When the electron is moving in the plane of the page in the direction indicated by the arrow, the force on the electron is directed finger east and your middle finger north. Your thumb points upward (representing the force on a positively charged object). 004 (part 1 of 2) 10.0 points [Show More]
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