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University of Tennessee - IE 483solution-manual-ebeling.

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CHAPTER 5 5.1 R t f t dt t dt t t t ( ) ( ) = ′ ′ = ( ) ' + ′ = + z∞ ∞ z 11 2 1 1 a) R t t R s s ( ) (. ) . = − − . + LMN OPQ → = − − LMN OPQ 1 1 1 = 1 5 1 1 ... 1 15 96296 3 3 b) 1 1 1 1 999 3 − − + LMN OPQ = t . 1- 1 t +1 = − → ( . ) 1 999 1 3 / t = 1- (1-.999)1/3 −1 − = 1 1111 . yrs = 40.55 days c) R(. ) . 1 .5 15 = = 667 = 3 .667 x=2 3 R x s x x (. ) . . 5 . . . . . 3 = F 667 333 3 2 3 333 667 44444 296741 741185 ∑H G I K Jb g b g b g b g b g − + = + = 5.2 R = − − ⋅ = 1 1 4 97 95 b g . . . n 1 4 1 95 97 8 components 1 95 97 1 4 − = − → = 7 598 − − . . /. ln . /. = → ln . b gn n . 5.3 (i) R e e e s( ) 100 1 1 = − − = − = d i − − − 100 1000 / / / 2 2 100 1000 200 1000 .99094 (ii) R e e s( ) 100 = ⋅ = −b g 100 10 000 / , 2 −.00005( ) 100 .99491 (higher reliability) 5.4 a) R R R R R R top = ⋅ − − ⋅ = − − 1 1 b g b g 2 2 1 1 2 and R R bottom = 3 R R R s = − − − ⋅ 1 1 1 ( )( ) top bottom R b) Rtop = − − = . . . 9 1 1 9 8019 2 b g2 and Rbottom = = . . 9 729 3 R s = − − − ⋅ = 1 1 8019 1 729 9 85168 ( . )( . ) . . 5.5 R t e e ( ) = − − 1 1 c − − . . 1th3 − t MTTF / → = − − = R e e ( ) 5 1 1 c 1 5 ( )h3 −5/ MTTF .85 . . ln . . . 93908 85 / 5 85 93908 e−5 MTTF = → = MTTF 5017 − FGH IJK = 5.6 R t e e R e s t t s ( ) i i i i ( ) . . . . = = → = − = FGH IJK − FGH IJK − FGH IJK ∑= θ θ θ 1 10 8 8 8 10 10 1 1 99 [Show More]

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