Physics > QUESTIONS & ANSWERS > Physics 30: Assignment 13, With 2 paarts<Part One: Blackbody Radiation and the Quantum and Part Two: (All)
ASSIGNMENT 13 Part One: Blackbody Radiation and the Quantum Part One of this assignment is worth 27 marks. The value of each question is noted in parentheses in the left margin. Note: The answer ar... eas will expand to fit the length of your response. (3) 1. Describe the pattern of intensity vs wavelength observed in blackbody experiments and explain why these observations were in conflict with the prediction of classical physics. (2) 2. What is the frequency of a 13.0 eV photon? z (2) 3. What is the wavelength of a 4.30 x 10-19 J photon? Answer: Ek= (4) 4. How many photons with a wavelength of 532 nm are released each second by a 5.0 mW laser? ) 5. When welders are working on pipelines they wear filters that block UV light. Why is this safety precaution necessary? Answer: UV radiation can cause permanent eye damage so it is important to block out levels of radiation harmful to us. Because our eyes are not able to process light outside the visible spectrum, the UV radiation actually causes damage. UV radiation can also cause skin cancer, so it is important to protect the rest of the body from it as well. (3) 6. A person lives near a 50 kW radio tower. Why is it safe to live near a high power radio tower but dangerous to be exposed to an x-ray machine that uses 7.5 kW? (2) 7. Why did the introduction of the photon effectively end classical p Part Two: The Photoelectric Effect Part Two of this assignment is worth 31 marks. The value of each question is noted in the left margin in parenthesis. Note: The answer areas will expand to fit the length of your response. 1. (3) While conducting research into the design of a light sensor, scientists measured the kinetic energy of photoelectrons that had been ejected from an unknown metal surface. The metal was exposed to various frequencies of EMR and the stopping voltage was measured to obtain the kinetic energy of the photoelectrons. The following data was obtained. Incident EMR frequency x 1014 Hz Kinetic energy of photoelectrons (eV) 6.0 0.38 7.0 0.80 8.0 1.20 9.0 1.63 10.0 2.04 a. Using the data above, plot a kinetic energy vs. frequency graph and use it to answer questions b – e. [Show More]
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