Statistics > QUESTIONS & ANSWERS > Questions and Answers > The University of NewcastleSTAT 1060STAT1060 PART B. 100% score (All)

Questions and Answers > The University of NewcastleSTAT 1060STAT1060 PART B. 100% score

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TAT1060: Assignment 3 (Part B) Question Two i) Let µ be the population mean of the amount of time students spend on the internet per week. HO: µ = 26 Hours HA: µ ¹ 26 Hours P-value= 0.0010 ... Assumptions: It is stated that the data is random selected, and the sample size is more than 30. Decision: As the p-value (0.010) is less than 0.05, the null hypothesis is rejected at the 5% significance level. Conclusion: There is enough evidence, at the 5% significance level, to suggest that the mean amount of time spent on the internet per week during COVID-19 is statistically different from 26 hours. ii) To determine the interval Lower: Mean – Confidence Level (95.0%) 25.0707 – 0.5439 = 24.5268 Upper: Mean + Confidence Level (95.0%) 25.0707 + 0.5439 = 25.6146 95%CI: (24.5268, 25.6146) iii) We are 95% confident that the population mean for the amount of time students spend on the internet during the week lies in between 24.5268 and 25.6146 hours. C3328290 Question Three Let µDIFF be the population mean difference in male and female patient ages who have died from COVID-19. HO: µDIFF = 0 HA: µDIFF ¹ 0 P-value= 0.4113 Assumptions: The data was randomly selected, and the sample size is greater than 30. Decision: As the p-value (0.4113) is greater than 0.05, the null hypothesis is not rejected at the 5% significance level. Conclusion: There is enough evidence, at the 5% significance level, to suggest that the mean age differences between male and females’ patients who die of COVID-19 is not statistically different. [Show More]

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