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BIOLOGY LAB EXPERIMENT : Experiment 1- Selection and Differentiation of Body Inhabiting, Gram-Positive Bacteria

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Experiment 1- Selection and Differentiation of Body Inhabiting, Gram-Positive Bacteria” “Table 4: Experiment 1 Growth Conditions” “Surface Tested” “Growth (Good or Poor)” “Color (Re ... d or Yellow)” “Other Observations” “LB/Nutrient Agar” “MSA Agar” “Skin” Good Good Nutrient foggy, clear. MSA yellowish green Cover all of the medium “Nose” Good Good MSA: yellowish, white Nutrient: Clear but is slightly foggy. Dots on MSA. None of the nutrient plate. “Countertop/Other” Good Good Both whiteish color Growth was similar on both. “Control” Good Good Nutrient: clear MSA: yellowish MSA: colonies grew on the control side. “Post-Lab Questions” “1. What substance in MSA confers selectivity? Why?” High sodium chloride concentration gives selectivity to MSA. This is because the sodium chloride makes it difficult for bacteria to grow. Typically, the sodium chloride concentration is 7.5% since most bacteria cannot live in high salinity. “2. What substance makes MSA differential? Why?” Mannitol is fermented by staph aureus which helps differentiate it from other Staph species. “3. What purpose does phenol red serve in MSA?” Phenol serves as a pH indicator. “4. Why are the nutrient agar plates used in this experiment?” Nutrient agar plate provides the necessary nutrients or organic carbon for the bacteria to grow. “Insert photo of your cultures after incubation with your name clearly visible in the background:” [Show More]

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