Business > CASE STUDY > Finite Mathematics JZM1 task 3.docx JZM1 – Finite Mathematics Task 3: Order of Oper (All)
Finite Mathematics JZM1 task 3.docx JZM1 – Finite Mathematics Task 3: Order of Oper
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Finite Mathematics JZM1 task 3.docx JZM1 – Finite Mathematics Task 3: Order of Operations Part A: Explain why 2 + 3(x -2) = 5x – 10 is not true as a rule To explain why this stat ... ement is not true as a rule, we must look at the order of operations or PEMDAS and solve the equation. To find the solution, we must first solve for x and then we can use the number found to plug back in to the equation and see if it is actually a true statement. To solve this equation using PEMDAS, the process would look like this: Problem with steps Steps explained 2 + 3(x – 2) = 5x – 10 Start with the original problem 2 + 3x – 6 = 5x - 10 Distribute the 3 to the numbers that were inside the parenthesis 3x – 4 = 5x - 10 combine the like terms of 2 and – 6 with the result of -4 -2x – 4 = -10 To get x by itself on one side 5x is subtracted from both sides leaving the right side of the equation with – 2x the left side with just - 10 -2x = -6 The next step to get x by itself on one side of the equation is to add 4 to each side leaving the right side with -2x the left side with -6 x= 3 Now divide both sides by -2 to get x = 3 5 = 5 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . . . . .. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .. . .. .. . . . . . . . . . . . . . . . . . .. . . . . [Show More]
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